第1个回答 2012-03-01
∫(0→1) x²e^x dx
= ∫(0→1) x² de^x
= [x²e^x] |(0→1) - ∫(0→1) 2xe^x dx，分部积分
= e - 2∫(0→1) x de^x
= e - 2[xe^x] |(0→1) + 2∫(0→1) e^x dx，分部积分
= e - 2e + 2[e^x] |(0→1)
= -e + 2(e - 1)
= e - 2本回答被提问者采纳
= ∫(0→1) x² de^x
= [x²e^x] |(0→1) - ∫(0→1) 2xe^x dx，分部积分
= e - 2∫(0→1) x de^x
= e - 2[xe^x] |(0→1) + 2∫(0→1) e^x dx，分部积分
= e - 2e + 2[e^x] |(0→1)
= -e + 2(e - 1)
= e - 2本回答被提问者采纳
第2个回答 2012-03-01
(∫上1下0)x^2 e^x dx=(∫上1下0)x^2de^x
=e-(∫上1下0)2xe^xdx=e-2(∫上1下0)2xe^xdx
=e-2e+2(∫上1下0)e^xdx=-e+2e-2=e-2
=0.71828
=e-(∫上1下0)2xe^xdx=e-2(∫上1下0)2xe^xdx
=e-2e+2(∫上1下0)e^xdx=-e+2e-2=e-2
=0.71828
第3个回答 2012-03-01
it has been solved cleerly in the picture
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