太谢谢你了!
还有一个问题,可以帮我算一下吗?
若0≤a≤π时,求使函数f(x)为偶函数的a值
解答题做法
f(x)为偶函数
f(-x)=f(x)
∴sin[-2x+(a+π/3)]=sin[2x+(a+π/3)]
∴sin(-2x)cos(a+π/3)+cos(-2x)sin(a+π/)
=sin2xcos(a+π/3)+cos2xsin(a+π/)
∴-sin2xcos(a+π/3)+cos2xsin(a+π/)
=sin2xcos(a+π/3)+cos2xsin(a+π/)
∴sin2xcos(a+π/3)=0
∵sin2x是变量
∴cos(a+π/3)=0
∴a+π/3=kπ+π/2,k∈Z
∵0≤a≤π
∴取k=0,a=π/6