1.f(x)=cos^2(x/2)+√3sin(x/2)cos(x/2)+a=(1/2)(cosx+1)+(√3/2)sinx+a
=(√3/2)sinx+(1/2)cosx+1/2+a=sin(x+π/6)+1/2+a
点(π/3,2)代入, sin(π/3+π/6)+1/2+a=2, a=1/2
2.f(x)=sin(x+π/6)+1, 最小正周期=2π,
当0≤x≤π时, π/6≤x+π/6≤7π/6, -1/2≤sin(x+π/6)≤1,
1/2≤sin(x+π/6)+1≤2, 所以值域为[1/2, 2]
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