化简(a^2-1/a^2+2a+1)/(a^2-a/a+1)

如题所述

(a^2-1/a^2+2a+1)/(a^2-a/a+1)
=[(a-1)(a+1)/(a+1)^2]/a(a-1)/(a+1)
=(a-1)/(a+1)×(a+1)/[a(a-1)]
=1/a
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第1个回答  2012-05-07
(a^2-1/a^2+2a+1)/(a^2-a/a+1)
=(a-1)(a+1)/(a+1)²÷a(a-1)/(a+1)
=a
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