积ååºåæä¼æ¾ å°±æ¯ä¸ç¥é被积å½æ°æä¹æ¾...å¯ä»¥è¯¦ç»ç¹ç»æ解éä¸å 谢谢
追ç积ååºé´ç¡®å®æ¯ [1ï¼2] åï¼è¢«ç§¯å½æ°å°±æ¯ä»å·¦ç§¯å°å³ï¼
å·¦è¾¹æ¯ x = -yï¼å³è¾¹æ¯ x = -1/yï¼æ以被积å½æ°å°±æ¯ å³ - å·¦ = -1/y - (-y)
è½å¸®æçççæ¡æ¯ä»ä¹ææåï¼
çæ¡ç¨å«éº»ç¦ï¼æ¯æåºååæäºä¸¤åï¼ç´çº¿ x = -1 为çï¼ï¼éçä¸æ ·ã
顺便æåºï¼çæ¡ç»åºçå¼å并ä¸æ£ç¡®ï¼èæ¯å¼æ°å¥½ç¢°å¯¹äºã
第å个积ååºé´åºè¯¥æ¯ -y -> -1 ï¼-y æ¯ä¸éï¼-1 æ¯ä¸éï¼