解法一：运用公式(u/v)'=(u'v-uv')/v²解
[1/(x+1)]'
=[1'·(x+1)-1·(x+1)']/(x+1)²
=（0-1·1)/(x+1)²
=-1/(x+1)²
解法二：运用公式(xⁿ)'=nxⁿ⁻¹解
[1/(x+1)]'
=(-1)·(x+1)'/(x+1)²
=-1/(x+1)²
[1/(x+1)]'
=[1'·(x+1)-1·(x+1)']/(x+1)²
=（0-1·1)/(x+1)²
=-1/(x+1)²
解法二：运用公式(xⁿ)'=nxⁿ⁻¹解
[1/(x+1)]'
=(-1)·(x+1)'/(x+1)²
=-1/(x+1)²
温馨提示：内容为网友见解，仅供参考
无其他回答
相似回答
