解方程 (x-5分之x-4)-(x-6分之x-5)=(x-8分之x-7)-(x-9分之x-8)速度
1 \/ [(x-5)\/(x-6)] = 1 \/ [(x-8)(x-9)]所以:(x-5)(x-6)=(x-8)(x-9)x^2-11x+30=x^2-17x+72 6x=42 x=7 带入原方程:左边=-1\/2 右边=-1\/2 左边=右边 ∴x=7是原方程的解
解方程,(x-4\/x-5) -(x-5\/x-6)=(x-7\/x-8)-(x-8\/x-9) 要详细一些,越快越...
解(x-4\/x-5) -(x-5\/x-6)=[﹙x-4﹚·﹙x-6﹚-﹙x-5﹚·﹙x-5﹚]/[﹙x-5﹚·﹙x-6﹚]=﹣1/[﹙x-5﹚·﹙x-6﹚]﹙x-7\/x-8)-(x-8\/x-9)=[﹙x-7﹚·﹙x-9﹚-﹙x-8﹚·﹙x-8﹚]/[﹙x-8﹚·﹙x-9﹚]=﹣1/[﹙x-8﹚·﹙x-9﹚]∴原式解得﹙...
(x-4\/x-5)-(x-7\/x-8)=(x-5\/x-6)-(x-8\/x-9)解方程 帮我解出来,写过程...
两边分别通分: 1\/(x-5)(x-8)=1\/(x-6)(x-9)然后两边都取倒数.. (x-5)(x-8)=(x-6)(x-9)展开得 2x=14所以x=7
解方程:x-4\/x-5 ➕x-8\/x-9=x-5\/x-6➕x-7\/x-8
1\/{(x-9)(x-8)} = 1\/{(x-6)(x-5)} (x-9)(x-8) = (x-6)(x-5)x²-17x+72=x²-11x+30 -6x=-42 x=7 经检验x=7是原方程的解
(x-3\/x-2)-(x-5\/x-4)=(x-7\/x-6)-(x-9\/x-8)(解方程)
(x-3\/x-2)-(x-5\/x-4)=(x-7\/x-6)-(x-9\/x-8)改写成 (1-1\/x-2)-(1-1\/x-4)=(1-1\/x-6)-(1-1\/x-7),然后把括号去掉,1就消掉了,然后再通分计算,没有好办法,这样运算量会小一些,希望你会看懂我写的式子,按你的写法写的 ...
如何解方程(x-4)\/(x-5)+(x-8)\/(x-9)=(x-7)\/(x-8)+(x-5)\/(x-6)
(x-4)\/(x-5)=(x-5+1)\/(x-5)=1+(1\/(x-5))原方程装换为 1+(1\/(x-5))+1+(1\/(x-9))=1+(1\/(x-8))+1+(1\/(x-6))1\/(x-5)+1\/(x-9)=1\/(x-8)+1\/(x-6)设x-7=y 1\/(y+2)+1\/(y-2)=1\/(y-1)+1\/(y+1)2y\/(y*y-4)=2y\/(y*y-1)y=0,x=7...
解方程:(x-5)\/(x-7)+(x-2)\/(x-4)=(x-3)\/(x-5)+(x-4)\/(x-6)
1\/(x-7)+1\/(x-4)=1\/(x-5)+1\/(x-6)(x-4+x-7)\/(x-4)(x-7)=(x-6+x-5)\/(x-5)(x-6)(2x-11)\/(x^2-11+28)=(2x-11)\/(x^2-11+30)因为x^2-11+28不等于x^2-11+30 分母不等,要等式成立只能分子为0 2x-11=0 x=11\/2 经检验,x=11\/2是原方程的解 ...
解方程: (x-5)\/(x+7)+(x-2)\/(x-4)= (x-3)\/(x-5)+(x-4)\/(x-6) 要过程
先把右边的移到左边(x-5)\/(x+7)-(x-3)\/(x-5)+(x-2)\/(x-4)-(x-4)\/(x-6)=0 再通分,得[(x-5)(x-5)-(x-3)(x-5)]\/[(x+7)(x-5)]+[(x-2)(x-4)-(x-4)(x-4)]\/[(x-4)(x-6)]=0 再整理,可得-2\/(x+7)+2\/(x-6)=0 即2\/(x+7)=2\/(x-6)
解方程(x-1\/x-2)+(x-7\/x-8)=(x-3\/x-4)+(x-5\/x-6)
(x-2+1)\/(x-2)+(x-8+1)\/(x-8)=(x-4+1)\/(x-4)+(x-6+1)\/(x-6) (此步对分子加1减1,是简便算法)1+1\/(x-2)+1+1\/(x-8)=1+1\/(x-4)+1+1\/(x-6)1\/(x-2)+1\/(x-8)=1\/(x-4)+1\/(x-6)1\/(x-8)-1\/(x-4)=1\/(x-6)-1\/(x-2) (此步移项...
解方程(x-1\/x-2)+(x-7\/x-8)=(x-3\/x-4)+(x-5\/x-6)
(x-2+1)\/(x-2)+(x-8+1)\/(x-8)=(x-4+1)\/(x-4)+(x-6+1)\/(x-6)(此步对分子加1减1,是简便算法)1+1\/(x-2)+1+1\/(x-8)=1+1\/(x-4)+1+1\/(x-6)1\/(x-2)+1\/(x-8)=1\/(x-4)+1\/(x-6)1\/(x-8)-1\/(x-4)=1\/(x-6)-1\/(x-2)(此步移项成左右...