在线等 PHP将同一个多维数组中的某一个元素（该元素是数组）下的数据合并成一个元素
Array
(
[0] => Array
(
[count] => 3
[totalPages] => 1
[totalRows] => 3
[nowPage] => 1
[html] =>
[data] => Array
(
[0] => Array
(
[sid] => 35
[mid] => 150
[uid] => 1
[flag] => photo
[title] => 1
)
[1] => Array
(
[sid] => 18
[mid] => 150
[uid] => 1
[flag] => photo
[title] => 1
)
)
)
[1] => Array
(
[count] => 1
[totalPages] => 1
[totalRows] => 1
[nowPage] => 1
[html] =>
[data] => Array
(
[0] => Array
(
[sid] => 24
[mid] => 242
[uid] => 253
[flag] => blog
[title] => 博文第一条
)
)
)
)
《《《《《《《想要的结果》》》》
Array
(
[0] => Array
(
[count] => 4
[totalPages] => 1
[totalRows] => 3
[nowPage] => 1
[html] =>
[data] => Array
(
[0] => Array
(
[sid] => 35
[mid] => 150
[uid] => 1
[flag] => photo
[title] => 1
)
[1] => Array
(
[sid] => 18
[mid] => 150
[uid] => 1
[flag] => photo
[title] => 1
)
[2] => Array
(
[sid] => 24
[mid] => 242
[uid] => 253
[flag] => blog
[title] => 博文第一条
)
)
)
$temp = array ();
//把想要的数组放到 $temp
foreach($ary as $key=>$val) {
if(is_array($val['data'])) {
foreach ($val['data'] as $k=>$v) {
$temp[] = $v;
}
}
}
最后一步，所收集到的数组放到第一个元素中
$ary[0]['data'] = $temp;
应该没有问题的吧。你试一下。如果不行。欢迎呼叫我。
[totalRows] => 3
[nowPage] => 1
[html] =>
这四个值是拿第一个元素的吗？，不需要加？
不知道这样合并有什麽用。代码如下。
<?php
$a = array(
array(
'count'=>3,
'totalPages'=>1,
'totalRows'=>3,
'nowPage'=>1,
'html'=>'',
'data'=>array(
array(
'sid'=>35,
'mid'=>150,
'uid'=>1,
'flag'=>'photo',
'title'=>1
),
array(
'sid'=>18,
'mid'=>150,
'uid'=>1,
'flag'=>'photo',
'title'=>1
)
)
),
array(
'count'=>1,
'totalPages'=>1,
'totalRows'=>1,
'nowPage'=>1,
'html'=>'',
'data'=>array(
array(
'sid'=>24,
'mid'=>242,
'uid'=>253,
'flag'=>'blog',
'title'=> '博文第一条'
)
)
)
);
echo '原始数组<br>';
echo '<pre>';
print_r($a);
echo '</pre>';
$b = array();
$b[0]['totalPages'] = $a[0]['totalPages'];
$b[0]['totalRows'] = $a[0]['totalRows'];
$b[0]['nowPage'] = $a[0]['nowPage'];
$b[0]['html'] = $a[0]['html'];
foreach($a as $data){
$b[0]['count'] = isset($b[0]['count'])? $b[0]['count']+$data['count'] : $data['count'];
if(!isset($b[0]['data'])){
$b[0]['data'] = array();
}
foreach($data['data'] as $val){
array_push($b[0]['data'], $val);
}
}
echo '合并后';
echo '<pre>';
print_r($b);
echo '</pre>';
?>追问
'count'需要加
'totalPages'需要除以10取整{floor()系统函数取到的结果}
'totalRows'=>3,需要加
'nowPage'=>1,不需要加
'html'=>'',
另外 最外层的数组 元素个数不确定·····
$newarr = array();
foreach ($arr as $k=>$v){
$newarr[0][$v['count']] = (isset($newarr[0][$v['count']]) ? $newarr[0][$v['count']]+$v['count'] : $v['count']);
...
$newarr[0][$v['data']] = (isset($newarr[0][$v['data']]) ? array_merge($newarr[0][$v['data']],$v['data']) : $v['data']);
}
var_dump($newarr);
手写伪代码，不保证正确，仅供思路参考本回答被网友采纳
