原式=2(a+1)/(a+1)(a-1)-(a+1)(a-1)/(a-1)²
=2/(a-1)-(a+1)/(a-1)
=(2-a-1)/(a-1)
=-(a-1)/(a-1)
=-1
=2/(a-1)-(a+1)/(a-1)
=(2-a-1)/(a-1)
=-(a-1)/(a-1)
=-1
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第1个回答 2012-04-25
(a^2-1)/(a-1) -√(a^2-2a+1) / (a^2-a) =a+1-√(a-1)^2 / a(a-1) =a+1-(1-a) / a(a-1) =a+1+1/a =2-√3+1+,
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