(1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10+1\/11+1\/12+1\/13+1\/14+1\/15...
这是调和数列,没有简便方法 定义1:自然数的倒数组成的数列,称为调和数列. 定义2:若数列{an}满足1\/a(n+1)-1\/an=d(n∈N*,d为常数),则称数列{an}调和数列 人们已经研究它几百年了.但是迄今为止没有能得到它的求和公式只是得到它的近似公式(当n很大时): 1+1\/2+1\/3+...+1\/n≈...
(1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10+1\/11+1\/12+1\/13+1\/14+1\/15...
所以将N分别取15到2 提取公因式1\/2 最后变成(1+3+4+...+14)\/2=52.5
小学 奥数 算式(1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10+1\/11+1\/12+...
2004\/13=154.153846153846是一个6位的循环,小数点后第2004位,2005位是61 42+66+81+61=250 所以算式(1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10+1\/11+1\/12+1\/13)×2004计算结果的小数点后第2004位数字是5
1+1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10=多少
计算1+1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10的过程如下:首先,我们可以通过拆分求和的方法简化计算:= 1 + (1\/2 + 1\/3 + 1\/6) + (1\/4 + 1\/5 + 1\/10) + 1\/7 + 1\/8 + 1\/9 = 1 + 1 + (1\/2 + 1\/3 - 1\/6) + (1\/4 + 1\/5 + 1\/10)= 1 +...
1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10等于多少?
1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10 =(1\/2+1\/3+1\/6)+(1\/4+1\/5+1\/10)+1\/7+1\/8+1\/9 =1+11\/20+1\/8+1\/7+1\/9 =1+27\/40+1\/9+1\/7 =1+283\/360+1\/7 =1+2341\/2520 =4861\/2520
小学数学1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10=?
1\/2+1\/3+1\/4+1\/5+1\/6+1\/10+1\/9+1\/8+1\/7 = 30\/60+ 20\/60+ 15\/60+ 12\/60+ 10\/60+ 6\/60+ 8\/72+ 9\/72+ 1\/7 = 50\/60+ 27\/60+ 16\/60 +17\/72 +1\/7 = 93\/60+ 85\/360+ 1\/7 = 558\/360+ 85\/360+ 1\/7 = 643\/360+ 360\/2520 = 4501\/2520+ 360\/2520 =...
1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10+...1\/100这道题怎样简算_百度知 ...
没有,这是调和数列,很早就有数学家研究,比如中世纪后期的数学家Oresme在1360年就证明了这个级数是发散的。他的方法很简单: 1 +1\/2+1\/3 +1\/4 + 1\/5+ 1\/6+1\/7+1\/8 +... 1\/2+1\/2+(1\/4+1\/4)+(1\/8+1\/8+1\/8+1\/8)+... 注意后一个级数每一项对应的分数都小于调和级数...
1+1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10。计算结果。
1+1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10 =1+(1\/2+1\/3+1\/6)+(1\/4+1\/5+1\/10)+1\/7+1\/8+1\/9 =1+1+11\/20+1\/8+1\/7+1\/9 =1+1+27\/40+1\/9+1\/7 =1+1+283\/360+1\/7 =1+1+2341\/2520 =1+4861\/2520 ≈2.92896 ...
1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10
分母是2的倍数通分加一起,是3倍数的加一起,是5倍数的加一起,是7倍数的加一起.不要重复.接着相加.可以试一试.
...竞赛题:1+1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10的循环节是多少...
1=1.175 1\/3、1\/6、1\/7、1\/9产生循环节,最小公约数126,相加 = (42 + 21 + 18 + 14)\/126 = 95\/126 = 0.7 539682 539682 ……混循环,循环节是539682 1\/2+1\/3+1\/4+1\/5+1\/6+1\/7+1\/8+1\/9+1\/10结果 = 1.928 968253 968253 968253……因此最终循环节是968253 ...