那几个发光二极管自己加就行了
s_set bit p1.0
m_set bit p1.1
h_set bit p1.2
second equ 30h
minute equ 31h
hour equ 32h
tcnt equ 34h
org 0000h
sjmp start
org 000bh
ljmp int_t0
start:mov dptr,#table
mov hour,#0
mov minute,#0
mov second,#0
mov tcnt,#0
mov tmod,#01h
mov th0,#3ch
mov tl0,#0b0h
mov ie,#82h
setb tr0
a1:lcall display
jnb s_set,s1
jnb m_set,s2
jnb h_set,s3
ljmp a1
s1:lcall delay
jb s_set,a1
inc second
mov a,second
cjne a,#60,j0
mov second,#0
ljmp k1
s2:lcall delay
jb m_set,a1
k1:inc minute
mov a,minute
cjne a,#60,j1
mov minute,#0
ljmp k2
s3:lcall delay
jb h_set,a1
k2:inc hour
mov a,hour
cjne a,#24,j2
mov hour,#0
mov minute,#0
mov second,#0
ljmp a1
j0:jb s_set,a1
lcall display
sjmp j0
j1:jb m_set,a1
lcall display
sjmp j1
j2:jb h_set,a1
lcall display
sjmp j2
int_t0:mov th0,#3ch
mov tl0,#0b0h
inc tcnt
mov a,tcnt
cjne a,#20,retune
inc second
mov tcnt,#0
mov a,second
cjne a,#60,retune
inc minute
mov second,#0
mov a,minute
cjne a,#60,retune
inc hour
mov minute,#0
mov a,hour
cjne a,#24,retune
mov hour,#0
mov minute,#0
mov second,#0
mov tcnt,#0
retune:reti
display:mov a,second
mov b,#10
div ab
clr p3.4
movc a,@a+dptr
mov p0,a
lcall delay
setb p3.4
mov a,b
clr p3.5
movc a,@a+dptr
mov p0,a
lcall delay
setb p3.5
MOV A,MINUTE
MOV B,#10
div ab
clr p3.2
movc a,@a+dptr
mov p0,a
lcall delay
setb p3.2
mov a,b
clr p3.3
movc a,@a+dptr
mov p0,a
lcall delay
setb p3.3
mov a,hour
mov b,#10
div ab
clr p3.0
movc a,@a+dptr
mov p0,a
lcall delay
setb p3.0
mov a,b
clr p3.1
movc a,@a+dptr
mov p0,a
lcall delay
setb p3.1
ret
table:db 3fh,06h,5bh,4fh,66h
db 6dh,7dh,07h,7fh,6fh
delay:mov r6,#10
d1:mov r7,#250
djnz r7,$
djnz r6,d1
ret
end
可以给一个C的，不过这只是大概的框架，细节问题在没有在实际中用是很难发现的！
#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
sbit p10=P1^0; //定义端口，p10控制四个LED闪烁
uchar secshi=0,secge=0,minshi=0,minge=0,hourshi=0,hourge=0;
uint num=0,sec=0,min=0,hour=0;
uint time=5000;
unsigned char code LEDBUF[10]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
//定义数码管显示的0-9的代码
void delay(unsigned int z)
{ //延时程序
unsigned int x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);//如果是12MHz晶振，就是110us对应z=1
}
void display();
void main()
{TMOD=0x02;//T0定时器，模式2定时，8位定时
TH0=55; //定时1S的数据设置，定时200个机器周期后中断一次,0.2ms
TL0=55;
EA=1;ET0=1;TR0=1;//开启总中断，允许T0中断，开启T0中断
while(1)
{display();//显示时间 }
}
void time0() interrupt 1
{num++;//T0中断服务程序，定时中断一次后num加一
time --;
If(time <=2500)
{ P10=0;}
else
{ p10=1;}
If(!time)
{time=5000;
sec++;
if(sec==60)
{sec=0;
min++;//到60s,min加一，sec清零
if(min==60)
{min=0;
hour++;//到60分，hour加一，分清零
if(hour==24)
{hour=0;
min=0;//到24小时则所有时间清零，新的一天从零时开始计时
sec=0;
}
}
}
}
}
void display()
secge=sec%10;//秒的个位，秒除以10的余数
secshi=sec/10;//十位，秒整除10的商
minge=min%10;
minshi=min/10;
hourge=hour%10;
hourshi=hour/10;
P2=0xfe;//1111 1110，0选通一位数码管，
P0= LEDBUF [secge];//送秒的各位显示
delay(5);//延时一会儿
P2=0xfd;//选通下一位数码管，1111 1101
P0= LEDBUF [secshi];//送秒的十位显示
delay(5);
P2=0xfb;//1111 1011，选通再下一位
P0=0x40;//显示分与秒之间的那个点
delay(5);
P2=0xf7;//1111 0111，再下一位
P0= LEDBUF [minge];//分的个位
delay(5);
P2=0xef;//1110 1111
P0= LEDBUF [minshi];//分的十位
delay(5);
P2=0xdf;//1101 1111
P0=0x40;//分与时间的点
delay(5);
P2=0xbf;//1011 1111
P0= LEDBUF [hourge];//小时的个位
delay(5);
P2=0x7f;//0111 1111
P0= LEDBUF [hourshi];//小时的十位
delay(5);
}本回答被网友采纳
