编程实现s=1-2=3-4+...+97-98+99-100的计算

#include<iostream>
using namespace std;
int main()
{
int temp=0;
for (int i=1;i<=100;i++)
{
if (i%2==0)
{
temp-=i;
}
else
{
temp+=i;
}
}
cout<<"值为："<<temp<<endl;
return 0;
}

晕倒，呵呵，用C++写了，VB好像有人写了，大概过程都是一样，只是语法不同而已

i=1
s1=0
sum=0
while(1<100)
{
s1=i-(i+1)
sum=sum+s1
i=i+2
}

Dim a As Integer
Dim s As Integer
Private Sub Command1_Click()
s = 0
For i = 1 To 100
If i Mod 2 = 1 Then a = i
If i Mod 2 = 0 Then a = -i
s = s + a

Next i
Print s
End Sub本回答被提问者采纳