谁能用c++帮忙编写个简单计算器的程序

我想看一下代码，谢谢。
会根据回答给你分

#include "stdio.h"
#include "conio.h"
void main()
{
float a();
float b();
float c();
float d();
int e();
int opere;
clrscr();
printf(" ======================================\n");
printf(" 简 单 计 算 器 菜 单 功 能\n");
printf(" ===================================\n");
printf(" 1-----------------加法运算\n");
printf(" 2-----------------减法运算\n");
printf(" 3-----------------乘法运算\n");
printf(" 4-----------------除法运算\n");
printf(" 5-----------------取余运算\n");
printf(" 6-----------------退出\n");
printf("=======================================\n");
printf("请选择(0-6):");
scanf("%d",&opere);
switch(opere)
{
case 1:printf("两个数之和:%.2f",a());break;
case 2:printf("两数之差是:%.2f",b());break;
case 3:printf("两数之积是:%.2f",c());break;
case 4:printf("两数整除的商是:%.2f",d());break;
case 5:printf("两数取余是:%d",e());break;
case 6:printf("退出");break;
}
}
float a()
{
float num1,num2,result;
printf("请输入两个数（用空格分开):");
scanf("%f%f",&num1,&num2);
result=num1+num2;
return result;
}
float b()
{
float num1,num2,result;
printf("请输入两个数（用空格分开):");
scanf("%f%f",&num1,&num2);
result=num1-num2;
return result;
}
float c()
{
float num1,num2,result;
printf("请输入两个数（用空格分开):");
scanf("%f%f",&num1,&num2);
result=num1*num2;
return result;
}
float d()
{
float num1,num2,result;
printf("请输入两个数（用空格分开):");
scanf("%f%f",&num1,&num2);
result=num1/num2;
return result;
}
int e()
{
int num1,num2,result;
printf("请输入两个数（用空格分开):");
scanf("%d%d",&num1,&num2);
result=num1%num2;
return result;}

温馨提示：内容为网友见解，仅供参考

当前网址：https://11.t2y.org/zz/fp7qpqvm7.html