第3个回答 2016-06-16
package com.string.to;
public class Four {
public static void main(String args[]){
String t="a";
String s="advancea";
System.out.println(new Four().sort(t,s));
}
public int sort(String t,String s){
int count=0;
String[] k=s.split(t);
if(s.lastIndexOf(t)==(s.length()-t.length()))
count=k.length;
else
count=k.length-1;
if(count==0)
System.out.println("t do not founded in s");
else
return count;
return -1;
}