已知1/2=1+1/2,1/6=1/2-1/3,1/12=1/3-1/4,...计算1/2+1/6+1/12+1/20+1/30+1/42?

如题所述

题目中有错误。
应该是1/2=1-1/2,1/6=1/2-1/3…
把上面的信息代入下式:
得1-1/2+1/2-1/3+1/3-1/4…+1/6-1/7
=1-1/7
=6/7
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第1个回答  2019-12-25
裂项相消法,
1/2+1/6+1/12+1/20+1/30+1/42
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)+(1/6-1/7)
=1-1/7=6/7
第2个回答  2019-12-29
这个简单啊!
原式=1-1/2+1/2-1/3+1/3-1/4+
1/4-1/5+1/5-1/6+1/6-1/7
=1-1/7=6/7

1\/2=1-1\/2,1\/6=1\/2-1\/3,1\/12=1\/3-1\/4...请根据以上的规律计算:1\/6+1\/...
解:1\/6+1\/12+1\/20+1\/30+1\/42 =(1\/2-1\/3)+(1\/3-1\/4)+(1\/4-1\/5)+(1\/5-1\/6)+(1\/6-1\/7)=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7 =1\/2-(1\/3-1\/3)-(1\/4-1\/4)-(1\/5-1\/5)-(1\/6-1\/6)-1\/7 =1\/2-0-0-0-0-1\/7...

...根据上述规律计算下题:1\/2+1\/6+1\/12+1\/20+1\/30=
=1-1\/2+1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6 =1-1\/6 =5\/6

计算: 1÷(1\/2+1\/6+1\/12+1\/20...+1\/342+1\/380)=?
1\/6=1\/2-1\/3 1\/12=1\/3-1\/4 ……1\/342=1\/18-1\/19 1\/380=1\/19-1\/20 这些相加就是1-1\/20=19\/20 所以答案是20\/19

简便计算1\/2+1\/6+1\/12+1\/20+1\/30+1\/42?
原式=6\/7 解题分析 将分母6、12、20、30、42分解为2×3、3×4、4×5、5×6、6×7,然后再化简。1\/2+1\/6+1\/12+1\/20+1\/30+1\/42 =1\/2+1\/(2×3)+1\/(3×4)+1\/(5×6)+1\/(6×7)=1\/2+(1\/2-1\/3)+(1\/3-1\/4)+(1\/5-1\/6)+(1\/6-1\/7)=1\/2+1...

1\/2+1\/6+1\/12+1\/20+1\/30+1\/42的简便运算。
1\/2+1\/6+1\/12+1\/20+1\/30+1\/42 =1\/(1x2)+1\/(2x3)+1\/(3x4)+1\/(4x5)+1\/(5x6)+1\/(6x7)=(1 -1\/2) +(1\/2-1\/3)+...+(1\/6-1\/7)=1 -1\/7 =6\/7 异分母分数相加:1、异分母分数相加,先通分,再按同分母分数相加法去计算,最后要化成最简分数。例1:3\/4+5\/7...

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因为 1\/2=1-1\/2 1\/6=1\/2-1\/3 1\/12=1\/3-1\/4 ...1\/2450=1\/49-1\/50 所以原式=1-1\/2+1\/2-1\/3...+1\/49-1\/50 =1-1\/50=49\/50

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1\/6,1\/12这三个数分母通分都为12。1\/20,1\/30分母通分为60。所以,简便运算先算前三个数和最后一个数。原=1\/2+1\/6+1\/12+1\/42+1\/20+1\/30 =6\/12+2\/12+1\/12+1\/42+3\/60+2\/60 =9\/12+1\/42+5\/60 =9\/12+1\/42+1\/12 =10\/12+1\/42 =70\/84+2\/84 =72\/84 =6\/7 ...

1\/2+1\/6+1\/12+1\/20+1\/30+1\/42的简便运算?
【为通分重新组合】=(1\/2+1\/6+1\/12)+(1\/20+1\/30)+1\/42 =(6+2+1)\/12 +(3+2)\/60 +1\/42 =9\/12 +5\/60 +1\/42 【分数约分】=(9\/12 +1\/12) +1\/42 =10\/12 +1\/42 【约分】=5\/6 +1\/42 【通分】=35\/42 +1\/42 =36\/42 【约分】=6\/7 ...

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