采用结合律，分配律逆运算计算简便快捷。
2x1/5+4x2/11+4x2/5+3x4/11
=2x1/5+4x2/5+4x/2/11+3x4/11
=2x(1/5+4/5)+4x(2/11+3/11)
=2x5/5+4x5/11
=10/5+20/11
=(10x11)/55+(20x5)/55
=(110+100)/55
=210/55
=42/11
=3又9/11
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第1个回答 2020-03-21
解:简便运算如下:
2x1/5+4x2/11+4x2/5+3x4/11
=(2/5+8/5)+(8/11+12/11)
=10/5+20/11
=2+1又9/11
=3又9/11
2x1/5+4x2/11+4x2/5+3x4/11
=(2/5+8/5)+(8/11+12/11)
=10/5+20/11
=2+1又9/11
=3又9/11
第2个回答 2020-03-21
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