每次输入1000*1000的矩阵肯定崩溃,原因不明
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main()
{ clock_t start,finish;
double totaltime;
start=clock();
int line1, column1, column2;
int i, j, k;
printf("输入第一个矩阵的行数:\n");
scanf("%d", &line1);
printf("输入第一个矩阵的列数:\n");
scanf("%d", &column1);
printf("输入第一个矩阵的列数:\n");
scanf("%d", &column2);
long arr1[line1][column1], arr2[column1][column2],arr3[line1][column2];
//printf("输入第一个矩阵的元素(%d*%d):\n",line1,column1);
srand((unsigned)time(NULL));
for (i = 0; i < line1; i++)
{
for (j = 0; j < column1; j++)
{
arr1[i][j] =(long)rand()%10+1;
}
}
//printf("输入第二个矩阵的元素(%d*%d):\n", column1, column2); 因为在这里矩阵的乘法会要求第一个的列与第二个行相等
for (i = 0; i < column1; i++)
{
for (j = 0; j < column2; j++)
{
arr2[i][j] =(long)rand()%10+1;
}
}
long ret;
for (i = 0; i < line1; i++)
{
for (j = 0; j < column1; j++)
{
ret = 0;
for (k = 0; k < column2; k++)
{
ret += arr1[i][k] * arr2[k][j]; //按照矩阵的乘法规则进行运算
}
arr3[i][j] = ret;
}
}
for (i = 0; i<line1; i++)
{
for (j = 0; j<column1; j++)
printf("%ld ", arr1[i][j]);
printf("\n");
}
printf("\n");
for (i = 0; i<column1; i++)
{
for (j = 0; j<column2; j++)
printf("%ld ", arr2[i][j]);
printf("\n");
}
printf("输出的两个矩阵的乘法运算的结果是:\n");
for (i = 0; i<line1; i++)
{
for (j = 0; j<column2; j++)
printf("%ld ", arr3[i][j]);
printf("\n");
}
finish=clock();
totaltime=(double)(finish-start)/CLOCKS_PER_SEC;
printf("%f",totaltime);
printf("\n");
//system("pause");
return 0;
}