2x²+1=3x
2x²+1-3x=0
x²-3/2x+(3/4)^2-(3/4)^2+1/2=0
(x-3/4)^2=1/16
x-3/4=1/4或x-3/4=-1/4
x=1或x=1/2
2x²+1-3x=0
x²-3/2x+(3/4)^2-(3/4)^2+1/2=0
(x-3/4)^2=1/16
x-3/4=1/4或x-3/4=-1/4
x=1或x=1/2
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第1个回答 2011-08-07
2x²+1=3x
2x^2-3x=-1
x^2-(3/2)x=-1/2
x^2-(3/2)x+9/16=1/16
(x-3/4)^2=1/16
x-3/4=1/4或-1/4
所以x=1或x=1/2
2x^2-3x=-1
x^2-(3/2)x=-1/2
x^2-(3/2)x+9/16=1/16
(x-3/4)^2=1/16
x-3/4=1/4或-1/4
所以x=1或x=1/2
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