你用一个枚举变量存每一个月的天数，然后判断闰年与否，是的话就二月29天，根据输入输出枚举中的值就行，这个太简单了~~~追问
能不能给出答案啊？谢谢~~~~~
追答dwjchdu说的很清楚了，不过int mon_p[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int mon_r[12]={31,29,31,30,31,30,31,31,30,31,30,31};有点罗嗦了，如果你是要学C的话，这样的应该自己去尝试编~~~
#include "stdio.h"
mian()
{
int mon_p[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int year,month;
scanf("%d %d",&year,&month);
if((year%4==0&&year%100!=0)||year%400==0)
mon_p[1]=29;
printf("%d年%d月有%d天！",year,month,mon_p[month-1]);
else
//mon_p[1]=28; //如果你是循环多次运行的话，这里最好加这个
printf("%d年%d月有%d天！",year,month,mon_p[month-1]);
getch();
}
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第1个回答 2011-10-31
#include<stdio.h>
void main()
{
int year,month;
scanf("%d%d",&year,&month);
switch(month)
{
case 1:printf("%d月有31天\n",month);break;
case 2:if((year%4==0&&year%100!=0)||year%400==0)
printf("%d月有29天\n",month);
else printf("%d月有28天\n",month);break;
case 3:printf("%d月有31天\n",month);break;
case 4:printf("%d月有30天\n",month);break;
case 5:printf("%d月有31天\n",month);break;
case 6:printf("%d月有30天\n",month);break;
case 7:printf("%d月有31天\n",month);break;
case 8:printf("%d月有31天\n",month);break;
case 9:printf("%d月有30天\n",month);break;
case 10:printf("%d月有31天\n",month);break;
case 11:printf("%d月有30天\n",month);break;
case 12:printf("%d月有31天\n",month);break;
default:printf("输入错误\n");
}
}
void main()
{
int year,month;
scanf("%d%d",&year,&month);
switch(month)
{
case 1:printf("%d月有31天\n",month);break;
case 2:if((year%4==0&&year%100!=0)||year%400==0)
printf("%d月有29天\n",month);
else printf("%d月有28天\n",month);break;
case 3:printf("%d月有31天\n",month);break;
case 4:printf("%d月有30天\n",month);break;
case 5:printf("%d月有31天\n",month);break;
case 6:printf("%d月有30天\n",month);break;
case 7:printf("%d月有31天\n",month);break;
case 8:printf("%d月有31天\n",month);break;
case 9:printf("%d月有30天\n",month);break;
case 10:printf("%d月有31天\n",month);break;
case 11:printf("%d月有30天\n",month);break;
case 12:printf("%d月有31天\n",month);break;
default:printf("输入错误\n");
}
}
第2个回答 2011-10-31
#include "stdio.h"
mian()
{
int mon_p[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int mon_r[12]={31,29,31,30,31,30,31,31,30,31,30,31};
int year,month;
scanf("%d %d",&year,&month);
if((year%4==0&&year%100!=0)||year%400==0)
printf("%d年%d月有%d天！",year,month,mon_r[month-1]);
else
printf("%d年%d月有%d天！",year,month,mon_p[month-1]);
getch();
}
mian()
{
int mon_p[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int mon_r[12]={31,29,31,30,31,30,31,31,30,31,30,31};
int year,month;
scanf("%d %d",&year,&month);
if((year%4==0&&year%100!=0)||year%400==0)
printf("%d年%d月有%d天！",year,month,mon_r[month-1]);
else
printf("%d年%d月有%d天！",year,month,mon_p[month-1]);
getch();
}
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