1/(x-1)+1/(x-4)=1/(x-2)+1/(x-3)
(2x-5)/(x-1)(x-4)=(2x-5)/(x-2)(x-3)
因此2x-5=0, 得：x=5/2
或(x-1)(x-4)=(x-2)(x-3)=0, 得：x^2-5x+4=x^2-5x+6, 不符。
故只有一解为x=5/2
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1\/(x-1)+1\/(x-4)=1\/(x-2)+1\/(x-3)(2x-5)\/(x-1)(x-4)=(2x-5)\/(x-2)(x-3)因此2x-5=0, 得：x=5\/2 或(x-1)(x-4)=(x-2)(x-3)=0, 得：x^2-5x+4=x^2-5x+6, 不符。故只有一解为x=5\/2
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