解方程:x+1\/x+2-x+2\/x+3=x+5\/x+6-x+6\/x+7
(x+1)\/(x+2)-(x+2)\/(x+3)=(x+5)\/(x+6)-(x+6)\/(x+7)化简为:1\/[(x+2)(x+3)]=1\/[(x+6)(x+7)];所以:(x+2)(x+3)=(x+6)(x+7),即:5x+6=13x+42解得:x=-9\/2=-4.5
解方程x+1\/x+2+x+6\/x+7=x+2\/x+3+x+5\/x+6
1\/(x+6)(x+7)=1\/(x+2)(x+3)(x+6)(x+7)=(x+2)(x+3)13x+42=5x+6 8x=-36 x=-4.5 经检验x=-4.5是方程的根。
解方程:(x+1\/x+2)+(x+6\/x+7)=(x+2\/x+3)+(x+5\/x+6)
x+2 +1- 1 x+7 =1- 1 x+3 - 1 x+6 = 1 x+2 - 1 x+3即1 (x+6)(x+7)= 1 (x+2)(x+3),所以(x+6)(x+7)=(x+2)(x+3).x=-9 2 .经检验x=-9 2 是方程的根
解方程难题:(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+6)
解方程难题:(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+6)。解这道七年级竞赛题目,其实并不难,分母都比分子大一。
x+1\/x+2 + x+16\/x+7 =x+2\/x+3 + x+5\/x+6 多少了!要过程!!
(X+1\/X+2)-(X+2\/X+3)=(X+5\/X+6)-(X+6\/X+7)(X方+4X+3-X方-4X-4)\/(X方+5X+6)=(X方+12X+35-X方-12X-36)\/(X方+13X+42)X方+5X+6=X方+13X+42 -8X=36 X=-9\/2
解方程:(x+1)\/(x+2)-(x+2)\/(x+3)=1\/(x+7)-1\/(x+6)
x+2)(x+3)(x+6)(x+7)得:de(ac-bb)=bc(d-e)这时把原公式代入.把括号内的公式分解开并得出:de=bc,也就是(x+6)(x+7)=(x+2)(x+3)公式两边同时分解得出:8x=-36 于是得出X的解为:x=-9\/2 验算:将x=-9\/2代入原公式,公式两边同等于-4\/15.所以,答案为:x=-9\/2 ...
x+1分之x+2减去x+3分之x+4=x+5分之x+6减去X+7分之x+8 (解方程)
方程两边分别通分,得 [(x+2)(x+3)-(x+1)(x+4)]\/[(x+1)(x+3)]=[(x+6)(x+7)-(x+8)(x+5)]\/[(x+5)(x+7)]2\/[(x+1)(x+3)]=2\/[(x+5)(x+7)]则(x+5)(x+7)=(x+1)(x+3)x²+12x+35=x²+4x+3 8x=-32 x=-4 检验:x=-4时,原方程...
初二数学 解方程 x+2\/x+1+x+8\/x+7=x+6\/x+5+x+4\/x+3
-1\/(x+7) 两边通分可得 [(x+3)-(x+1)]\/[(x+3)(x+1)]=[(x+7)-(x+5)]\/[(x+7)(x+5)]即2\/[(x+3)(x+1)]=2\/[(x+7)(x+5)]∴(x+3)(x+1)=(x+7)(x+5)x²+4x+3=x²+12x+35 4x+3=12x+35 x=-4 经检验,x=-4是原方程的解!
解分式方程:(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+6)
x+3)+1\/(x+6)1\/(x+2)-1\/(x+3)=1\/(x+6)-1\/(x+7)(x+3-(x+2))\/(x+2)(x+3)=(x+7-(x+6))\/(x+6)(x+7)1\/(x+2)(x+3)=1\/(x+6)(x+7)(x+2)(x+3)=(x+6)(x+7)x^2+5x+6=x^2+13x+42 8x=-36 x=-9\/2 经检验,x=-9\/2是方程的根。
分式方程(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+
拆项: 1-1\/(x+2)+1-1\/(x+7)=1-1\/(x+3)+1-1\/(x+6)即: 1\/(x+2)+1\/(x+7)=1\/(x+3)+1\/(x+6)通分: (2x+9)\/(x+2)(x+7)=(2x+9)\/(x+3)(x+6)得:2x+9=0, 或(x+2)(x+7)=(x+3)(x+6)前者得x=-4.5, 后者无解 经检验,x=-4.5为原方程的解...