解方程:x+1/x+2-x+2/x+3=x+5/x+6-x+6/x+7

如题所述

(x+1)/(x+2)-(x+2)/(x+3)=(x+5)/(x+6)-(x+6)/(x+7)化简为:1/[(x+2)(x+3)]=1/[(x+6)(x+7)];所以:(x+2)(x+3)=(x+6)(x+7),即:5x+6=13x+42解得:x=-9/2=-4.5
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第1个回答  推荐于2020-12-25
x+1/x+2-x+2/x+3=x+5/x+6-x+6/x+7
((X^2+4X+3)-(X^2+4X+4))/(X^2+5X+6)=((X^2+12X+35)-(X^2+4X+36)/(X^2+13X+42)
-1/(X^2+5X+6)=-1/(X^2+13X+42)
X^2+5X+6=X^2+13X+42
X=-4.5本回答被网友采纳

解方程:x+1\/x+2-x+2\/x+3=x+5\/x+6-x+6\/x+7
(x+1)\/(x+2)-(x+2)\/(x+3)=(x+5)\/(x+6)-(x+6)\/(x+7)化简为:1\/[(x+2)(x+3)]=1\/[(x+6)(x+7)];所以:(x+2)(x+3)=(x+6)(x+7),即:5x+6=13x+42解得:x=-9\/2=-4.5

解方程x+1\/x+2+x+6\/x+7=x+2\/x+3+x+5\/x+6
1\/(x+6)(x+7)=1\/(x+2)(x+3)(x+6)(x+7)=(x+2)(x+3)13x+42=5x+6 8x=-36 x=-4.5 经检验x=-4.5是方程的根。

解方程:(x+1\/x+2)+(x+6\/x+7)=(x+2\/x+3)+(x+5\/x+6)
x+2 +1- 1 x+7 =1- 1 x+3 - 1 x+6 = 1 x+2 - 1 x+3即1 (x+6)(x+7)= 1 (x+2)(x+3),所以(x+6)(x+7)=(x+2)(x+3).x=-9 2 .经检验x=-9 2 是方程的根

解方程难题:(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+6)
解方程难题:(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+6)。解这道七年级竞赛题目,其实并不难,分母都比分子大一。

x+1\/x+2 + x+16\/x+7 =x+2\/x+3 + x+5\/x+6 多少了!要过程!!
(X+1\/X+2)-(X+2\/X+3)=(X+5\/X+6)-(X+6\/X+7)(X方+4X+3-X方-4X-4)\/(X方+5X+6)=(X方+12X+35-X方-12X-36)\/(X方+13X+42)X方+5X+6=X方+13X+42 -8X=36 X=-9\/2

解方程:(x+1)\/(x+2)-(x+2)\/(x+3)=1\/(x+7)-1\/(x+6)
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初二数学 解方程 x+2\/x+1+x+8\/x+7=x+6\/x+5+x+4\/x+3
-1\/(x+7) 两边通分可得 [(x+3)-(x+1)]\/[(x+3)(x+1)]=[(x+7)-(x+5)]\/[(x+7)(x+5)]即2\/[(x+3)(x+1)]=2\/[(x+7)(x+5)]∴(x+3)(x+1)=(x+7)(x+5)x²+4x+3=x²+12x+35 4x+3=12x+35 x=-4 经检验,x=-4是原方程的解!

解分式方程:(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+6)
x+3)+1\/(x+6)1\/(x+2)-1\/(x+3)=1\/(x+6)-1\/(x+7)(x+3-(x+2))\/(x+2)(x+3)=(x+7-(x+6))\/(x+6)(x+7)1\/(x+2)(x+3)=1\/(x+6)(x+7)(x+2)(x+3)=(x+6)(x+7)x^2+5x+6=x^2+13x+42 8x=-36 x=-9\/2 经检验,x=-9\/2是方程的根。

分式方程(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+
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