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1/(1*2)+1/(2*3)+1/(3*4)+1(4*5)......1/(49*50)这道题怎么做请求讲解,谢谢
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第1个回答 2012-12-20
1/[n*(n+1)]=(1/n)-[1/(n+1)]这叫裂项相消法,很有用,最终结果是1-1/50=49/50
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