x²+y²-2x+4y=20 (1)
(x-y)²-6x+6y+8=0 (2)
ç±(2)å¾(x-y)²-6(x-y)+8=0
(x-y-4)(x-y-2)=0
â´x-y-4=0 (3)
x-y-2=0 (4)
ç±(3)å¾x=y+4 (5)
æ(5)ä»£å ¥(1)å¾
(y+4)²+y²-2(y+4)+4y=20
2y²+10y-12=0
y²+5y-6=0
y+6=0 y-1=0
â´y=-6 y=1
æy=-6,y=1ä»£å ¥(3)å¾
x=-2 x=5
â´x=-2 x=5
y=-6 y=4
åç解(1)åï¼4ï¼å¾
(y+2)²+y²-2(y+2)+4y=20
2y²+6y-20=0
y²+3y-10=0
y+5=0 y-2=0
â´y=-5 y=2
æy=-6,y=1ä»£å ¥(4)å¾
x=-3 x=4
â´x=-3 x=4
y=--5 y=2
(x-y)²-6x+6y+8=0 (2)
ç±(2)å¾(x-y)²-6(x-y)+8=0
(x-y-4)(x-y-2)=0
â´x-y-4=0 (3)
x-y-2=0 (4)
ç±(3)å¾x=y+4 (5)
æ(5)ä»£å ¥(1)å¾
(y+4)²+y²-2(y+4)+4y=20
2y²+10y-12=0
y²+5y-6=0
y+6=0 y-1=0
â´y=-6 y=1
æy=-6,y=1ä»£å ¥(3)å¾
x=-2 x=5
â´x=-2 x=5
y=-6 y=4
åç解(1)åï¼4ï¼å¾
(y+2)²+y²-2(y+2)+4y=20
2y²+6y-20=0
y²+3y-10=0
y+5=0 y-2=0
â´y=-5 y=2
æy=-6,y=1ä»£å ¥(4)å¾
x=-3 x=4
â´x=-3 x=4
y=--5 y=2
温馨提示：内容为网友见解，仅供参考
第1个回答 2013-02-18
(x-y)²-6x+6y+8=0
(x-y)^2-6(x-y)+8=0
(x-y-2)(x-y-4)=0
x=y+2或x=y+4
(1)x=y+2
x²+y²-2x+4y=20
2y^2+6y-20=0
y^2+3y-10=0\
y1=2,y2=-5
(2)x=y+4
x²+y²-2x+4y=20
2y^2+10y-12=0\
y^2+5y-6=0
y1=1
y2=-6
答案
(x,y)=(4,2)(-3,-5)(5,1)(-2.-6)
(x-y)^2-6(x-y)+8=0
(x-y-2)(x-y-4)=0
x=y+2或x=y+4
(1)x=y+2
x²+y²-2x+4y=20
2y^2+6y-20=0
y^2+3y-10=0\
y1=2,y2=-5
(2)x=y+4
x²+y²-2x+4y=20
2y^2+10y-12=0\
y^2+5y-6=0
y1=1
y2=-6
答案
(x,y)=(4,2)(-3,-5)(5,1)(-2.-6)
第2个回答 2013-02-18
把第二个化成一般式 1-2 得出两圆相交弦的方程 用y表示x 然后代入求解 实际上是求两圆相交点的坐标
相似回答
