计算:[x+2分之x+1]+[x+7分之x+6]=[x+3分之x+2]-[x+6分之x+5]谢谢

解方程:x+2分之x+1+x+7分之x+6=x+3分之x+2+x+6分之x+5
x+x\/2+1+x+x\/7+6 = x+x\/3+2+x+x\/6+5 ==>x\/2+x\/7+7 = (x\/3+x\/6)+7 ==>x\/7 = 0 ==>x=0

解方程x+2分之x+1+x+7分之x+6=x+3分之x+2+x+6分之x+5
x+2分之x+1+x+7分之x+6=x+3分之x+2+x+6分之x+5 x+1\/x+2 + x+6\/x+7=x+2\/x+3+ x+5\/x+6 1-1\/x+2 + 1- 1\/x+7=1-1\/x+3+ 1-1\/x+6 1\/x+2 + 1\/x+7=1\/x+3+ 1\/x+6 (x+7+x+2)\/(x+2)(x+7)=(x+6+x+3)\/(x+3)(x+6)(2x+9)(x+2)(...

初二数学 解分式方程:X+2\/X+1 +X+8\/X+7 = X+6\/X+5 + X+4\/X+3
(x+2)\/(x+1)+(x+8)\/(x+7)=(x+6)\/(x+5)+(x+4)\/(x+3)(x+2)\/(x+1))-(x+4)\/(x+3))=((x+6)\/(x+5)-(x+8)\/(x+7)通分,2\/（x+1）（x+3）=2\/(x+5)(x+7)(x+1)(x+3)=(x+5)(x+7)x=-3\/2 ...

x+2\\x+1-x+4\\x+3=x+6\\x+5-x+8\\x+7简便
x+2）\/（x+1）-（x+4）\/（x+3）=（x+6）\/（x+5）-（x+8）\/（x+7）每个式子都减去1，就是从分子里减去分母，得到 1\/ （x+1）-1\/（x+3）=1\/（x+5）-1\/（x+7）移项，得到1\/（X+1）+1\/（X+7）=1\/（X+5）+1\/（X+3）合并得到（2X+8）\/（X+1）（X+7）=（2X+...

x+1分之x+2 -x+3分之x+4 =x+5分之x+6 -x+7分之x+8
原方程可化为[1+1\/(x+1)]-[1+1\/(x+3)]=[1+1\/(x+5)]-[1+1\/(x+7)]1\/(x+1)-1\/(x+3)=1\/(x+5)-1\/(x+7)2\/(x+1)(x+3)=2\/(x+5)(x+7)(x+1)(x+3)=(x+5)(x+7)x^2+4x+3=x^2+12x+35 8x+32=0 x=-4 ...

x+1分之x+2减去x+3分之x+4=x+5分之x+6减去X+7分之x+8 (解方程)
x+1分之x+2减去x+3分之x+4=x+5分之x+6减去X+7分之x+8 方程两边分别通分，得 [(x+2)(x+3)-(x+1)(x+4)]\/[(x+1)(x+3)]=[(x+6)(x+7)-(x+8)(x+5)]\/[(x+5)(x+7)]2\/[(x+1)(x+3)]=2\/[(x+5)(x+7)]则(x+5)(x+7)=(x+1)(x+3)x²+12...

分解因式(x+1)(x+2)(x+3)(x+6)+x^2 请说明解法及公式
(x+1)(x+2)(x+3)(x+6)+x*x =(x*x+7x+6)(x*x+5x+6)+x*x =[(x*x+6)+7x][(x*x+6)+5x]+x*x =(x*x+6)^2+12x(x*x+6)+35x*x+x*x =(x*x+6)^2+2*6x*(x*x+6)+36x*x =(x*x+6x+6)^2

解方程x+2分之x+1+x+9分之x+8=x+3分之x+2+x+8分之x+7
这道题有问题吧，没有解啊，方程两面的常数和都是9，原题写错了吧

2分之x加3分之2x加1=6分之x加5方程解
回答：x=6 话说需要过程么 x\/2+2x\/3+1=x\/6+5 4x\/6=4 x=6

(x+1)(x+3)分之2+(x+3)(x+5)分之2+(x+5)(x+7)分之2+……(x+2
2\/[(X+1)(X+3)]=1\/(X+1)-1\/(X+3) 2\/[(X+3)(X+5)]=1\/(X+3)-1\/(X+5)后面类同，然后叠加既可得到答案