(æ ¹å·18-æ ¹å·0.5+2æ ¹å·1/3ï¼-ï¼æ ¹å·1/8-æ ¹å· 12ï¼
=â18-â0.5+2â1/3-â1/8+â12
=3â2-â2/2+2â3/3-â2/4+2â3
=ï¼3-1/2-1/4ï¼â2+ï¼2/3+2ï¼â3
=9â2/4+8â3/3
楼ä¸çéäº
=â18-â0.5+2â1/3-â1/8+â12
=3â2-â2/2+2â3/3-â2/4+2â3
=ï¼3-1/2-1/4ï¼â2+ï¼2/3+2ï¼â3
=9â2/4+8â3/3
楼ä¸çéäº
温馨提示：内容为网友见解，仅供参考
第1个回答 2013-08-22
(√18-√0.5+2√1/3)-(√1/8-√12)
=[3√2-(√2)/2+(2√3)/3]-[(√2)/4-2√3]
=3√2-(√2)/2+(2√3)/3-(√2)/4-2√3
=(3-1/2-1/4)√2+(2/3-2)√3
=(9√2)/4-(4√3)/3
=[3√2-(√2)/2+(2√3)/3]-[(√2)/4-2√3]
=3√2-(√2)/2+(2√3)/3-(√2)/4-2√3
=(3-1/2-1/4)√2+(2/3-2)√3
=(9√2)/4-(4√3)/3
相似回答
