main()
{
int n,a,b=0;
printf("please enter a number !\n");
scanf("%d",&n);
printf("the number is %d\n",n);
for(a=n;a>0;){
b=b*10+a%10;
a=a/10;
}
printf("n=%d,b=%d\n",n,b);
if(b==n){
printf("yes!!!");
}else{
printf("yes!!!");
}
}
温馨提示：内容为网友见解，仅供参考
第1个回答 2018-03-30
#include ＂Stdio.h＂
#include ＂Conio.h＂
int main(void)
{
int i,k;
long n,m;
int digit[10];
clrscr();
puts(＂Please input a long number:＂);
scanf(＂%ld＂,&n);
m=n;k=0;
do
{
digit[k++]=m%10; /**//*保存最低位*/
m/=10; /**//*去掉最低位*/
}while(m!=0);
k--;
for(i=0;i<k;i++,k--) /**//*判断是否为回文数*/
if(digit[i]!=digit[k]) break; /**//*不相等,则不是回文数,推出循环*/
if(i<k) printf(＂%ld is not a huiwen number＂,n);
else printf(＂%ld is a huiwen number＂,n);
getch();
return 0;
}
本回答被网友采纳第2个回答 2016-11-21
# include <stdio.h>
int main(void){
int val;
int m;
int sum = 0;
printf("请输入您需要判断的数字:");
scanf("%d",&val);
m = val;
while (m){
sum = sum * 10 + m%10;
m /=10;
}
if(sum == val){
printf("Yes!\n");
}else{
printf("No!\n");
}
return 0;
}
int main(void){
int val;
int m;
int sum = 0;
printf("请输入您需要判断的数字:");
scanf("%d",&val);
m = val;
while (m){
sum = sum * 10 + m%10;
m /=10;
}
if(sum == val){
printf("Yes!\n");
}else{
printf("No!\n");
}
return 0;
}
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