按照实际计算的顺序，【相当于计算机计算时的顺序，也就是去掉括号后的计算顺序】，4个运算符只有4！= 4*3*2*1 = 24种。
因此，
5个5加减乘除各用1次，至多只有24个不同的结果。
下面列出这24种情形，
5+5 = 10, 10 - 5 = 5, 5*5 = 25, 25/5 = 5 [+-*/]
5+5 = 10, 10 - 5 = 5, 5/5 = 1, 1*5 = 5 [+-/*]
5+5 = 10, 10*5 = 50, 50-5 = 45, 45/5 = 9 [+*-/]
5+5 = 10, 10*5 = 50, 50/5 = 10, 10-5 = 5 [+*/-]
5+5 = 10, 10/5 = 2, 2-5 = -8, -8*5 = -40 [+/-*]
5+5 = 10, 10/5 = 2, 2*5 = 10, 10 - 5 = 5 [+/*-]
5 - 5 = 0, 0 + 5 = 5, 5*5 = 25, 25/5 = 5 [-+*/]
5 - 5 = 0, 0 + 5 = 5, 5/5 = 1, 1*5 = 5 [-+/*]
5 - 5 = 0, 0*5 = 0, 0 + 5 = 5, 5/5 = 1 [-*+/]
5 - 5 = 0, 0*5 = 0, 0/5 = 0, 0 + 5 = 5 [-*/+]
5 - 5 = 0, 0/5 = 0, 0 + 5 = 5, 5*5 = 25 [-/+*]
5 - 5 = 0, 0/5 = 0, 0*5 = 0, 0 + 5 = 5 [-/*+]
5*5 = 25, 25+5 = 30, 30-5 = 25, 25/5 = 5 [*+-/]
5*5 = 25, 25+5 = 30, 30/5 = 6, 6 - 5 = 1 [*+/-]
5*5 = 25, 25-5 = 20, 20+5 = 25, 25/5 = 5 [*-+/]
5*5 = 25, 25-5 = 20, 20/5 = 4, 4 + 5 = 9 [*-/+]
5*5 = 25, 25/5 = 5, 5 + 5 = 10, 10-5 = 5 [*/+-]
5*5 = 25, 25/5 = 5, 5-5 = 0, 0 + 5 = 5 [*/-+]
5/5 = 1, 1+5 = 6, 6 - 5 = 1, 1*5 = 5 [/+-*]
5/5 = 1, 1+5 = 6, 6*5 = 30, 30 - 5 = 25 [/+*-]
5/5 = 1, 1-5 = -4, -4+5 = 1, 1*5 = 5 [/-+*]
5/5 = 1, 1-5 = -4, -4*5 =-20,-20+5 = -15 [/-*+]
5/5 = 1, 1*5 = 5, 5 + 5 = 10, 10 - 5 = 5 [/*+-]
5/5 = 1, 1*5 = 5, 5 - 5 = 0, 0 + 5 = 5 [/*-+]
因为上面24个结果中没有4，
所以，
5个5加减乘除各用一次怎么也不可能等于4。
5-5 ×5 ÷5÷ 5=4
5+5-5-5÷5=4
5个5加减乘除各用一次怎么等于4可以用括号
5+5 = 10,10\/5 = 2,2-5 = -8,-8*5 = -40 [+\/-*]5+5 = 10,10\/5 = 2,2*5 = 10,10 - 5 = 5 [+\/*-]5 - 5 = 0,0 + 5 = 5,5*5 = 25,25\/5 = 5 [-+*\/]5 - 5 = 0,0 + 5 = 5,5\/5 = 1,1*5 = 5 [-+\/*]5 - 5 = 0,0*5 = 0,0 +...
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(5*5-5*5)\/5=0 [(5-5)\/5]+5\/5=1 (5+5-5+5)\/5=2 (5*5-5-5)\/5=3 5+5-(5\/5+5)=4
怎样用加减乘除法及小括号使5个5=4
5*5\/5-5\/5=4
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5个5用加减乘除括号怎样等于0,1,2,3,4,5
(5-5)×5×5×5=0, 5÷5+(5-5) ×5=1, (5+5)÷5+5-5=2, (5×5-5-5)÷5=3, (5×5÷5)-5÷5=4, 5×5×5÷5÷5=5.
55555等于4用5个5填加减乘除等于4
5-5÷5+5-5=4 很高兴为您解答!有不明白的可以追问！如果您认可我的回答。请点击下面的【选为满意回答】按钮，谢谢！
如何用5个5加减乘除只用一次算到24,加减乘除只用一次啊有重复的不要作...
我所知道的就以下几种解法：(5×5×5-5)÷5=24 5×(5-5÷5÷5)=24 5÷5=1 1. 常规方法：5*(5-1\/5)2. 几个特殊运算：(5-5\/5*1)!=4!=4*3*2*1=24 (5-1*5\/5)! 1*(5-5\/5)!(5-1)!*5\/5 5!\/(5+5mod1)=5!\/(5+0)√5 * √5 *5-1 ...
