#include <stdio.h>
void main()
{
int year,month,day;
int tempmonth,yearday;
int week,weekday;
unsigned int sum=0;
int tag=0;
printf("输入年、月、日:\n");
scanf("%d %d %d",&year,&month,&day);
tag =( year - 1980 )/4;
sum=(year-1984)*365 + tag;
tempmonth = month - 1;
yearday = 0;
switch(tempmonth)
{
case 12:yearday+=31;
case 11:yearday+=30;
case 10:yearday+=31;
case 9:yearday+=30;
case 8:yearday+=31;
case 7:yearday+=31;
case 6:yearday+=30;
case 5:yearday+=31;
case 4:yearday+=30;
case 3:yearday+=31;
case 2:yearday+=28;
case 1:yearday+=31;
}
yearday = yearday+day;
if ((year-1984)%4==0 && month > 2)
{
yearday+=1;
}
sum=sum+yearday;
if (year==1984)
{
sum-=1;
}
printf("距1984年1月1日一共有%d天\n",sum);
/*上面是计算输入的日期距1984年1月1日一共经历了多少天*/
weekday = (sum-1) % 7;
week = yearday / 7;
printf("今天是第%d个星期，星期%d",week,weekday);
return ;
}
下面是修改好的，能多给些分嘛？写程序不容易，还有，好好学习，这些不难，就是多花点时间而已
#include <stdio.h>
void main()
{
int year,month,day;
int tempmonth,yearday;
int week,weekday;
int sum=0;
int tag=0;
printf("输入年、月、日:\n");
scanf("%d %d %d",&year,&month,&day);
tag =( year - 1988 )/4;
printf("tag=%d\n",tag);
sum=(year-1990)*365 + tag;
tempmonth = month - 1;
yearday = 0;
switch(tempmonth)
{
case 12:yearday+=31;
case 11:yearday+=30;
case 10:yearday+=31;
case 9:yearday+=30;
case 8:yearday+=31;
case 7:yearday+=31;
case 6:yearday+=30;
case 5:yearday+=31;
case 4:yearday+=30;
case 3:yearday+=31;
case 2:yearday+=28;
case 1:yearday+=31;
}
yearday = yearday+day;
if ((year-1988)%4==0 && month > 2)
{
yearday+=1;
}
sum=sum+yearday;
printf("sum=%d\n",sum);
printf("距1990年1月1日一共有%d天\n",sum);
/*上面是计算输入的日期距1990年1月1日一共经历了多少天*/
weekday = (sum-1) % 7+1;
week = yearday / 7;
printf("今天是第%d个星期，星期%d",week,weekday);
return ;
}本回答被网友采纳
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