2x-1\/3-5x+1\/6=1怎么解?
(2x-1)\/3-(5x+1)\/6=1 2(2x-1)--(5x+1)=6 4x-2-5x-1=6 -x=9 x=-9
2x+1\/3-5x-1\/6=1怎么做,请把过程写下,
2x+1\/3-5x-1\/6=1 解: -3x+1\/6=1 -3x=5\/6 x=-(5\/18)
2x+1\/3-5x-1\/6=1怎么解
x=3 具体答案是:2x+1\/3-5x-1\/6=1 的解题是:4x+2-5x+1=6 x=3 x=3\/8 具体解法:2x+1\/2-5x=6 2x+1=12-30x x=3\/8
(2x+1)\/3-(5x-1)\/6=1 解x=? 急需···
两边同时乘以6 得4x+2-5x+1=6 -x=3 x=3
问方程2x+1\/3-5x-1\/6=1怎么解
两边乘6 2(2x+1)-(5x-1)=6 4x+2-5x+1=6 5x-4x=2+1-6 x=-3
2x+1\/3-5x-1\/6=1 怎么解?(用分数形式算)
3。(2x+4)-6。(3x-2)=7 同时乘(2x+5)(5x-7),得: 8(2x-0)-7(2x+8)=(2x+4)(8x-3) 03x-2-22x-8=40x2+2x-1 80x2=-20 x2=-0 无j实数解n瘛o
2x-1\/3-1-5x\/6=1
(2x--1)\/3--(1--5x)\/6=1 解: 去分母得:2(2x--1)--(1-5x)=6 去括号得:4x--2--1+5x=6 移项合并同类项得:9x=9 两边都除以9得:x=1.
2x+1\/3-5x-1\/6=1
解:-3X=1-1\/3+1\/6 -3X=5\/6 X=-5\/6*1\/3 =-5\/18
2x+1\/3-5x-1\/6=1,按照去分母,去括号这样一步骤一步骤的来,上课没听懂啊...
解:移项:2x-5x=1-1/3+1/6 合并: -3X=5/6 系数化为1:X=-5/18
下面是小红解方程2x+1\/3–5x–1\/6=1的过程,解:去分母,得2(2x+1...
(2x+1)\/3–(5x–1)\/6=1 去分母 2(2x+1)–(5x–1)=2 去括号 4x+2-5x+1=2 合并同类项并化简 3-x=2 x=1