54 3×6过程怎么写?
276+543×275 =276+(276+267)*275 =276(1+275)+267*275 =276*276+267*275 276×543-267 =276*(276+267)-267 =276*276+267(276-1)=276*276+276*275 所以原式=1
...③19931993×1993-19931992×1992-19931992 ④276+543
=(85-119)×10+(841819+105119)×38,=850-1019+190×38,=850-1019+7114,=850+7114-1019,=92114-1019,=9205576;(2)1321130÷131,=132×130+1130×1131,=132×130+1130×131,