第2个回答 2010-12-04
#include<iostream>
#include<vector>
#include<cmath>
#include<sstream>
using namespace std;
void main()
{
vector<char>v;
string s;
cout<<"请输入一个中间无空格的字符串:";
cin>>s;
istringstream sin(s);
for(char c;sin>>c;)
v.push_back(c);
vector<int>num;
for(int i=0;i<v.size();i++)
{
if((v[i]>='0')&&(v[i]<='9'))
{
if(i==v.size()-1)
{
num.push_back(v[i]-'0');
continue;
}
for(int j=i+1;(v[j]>='0')&&(v[j]<='9');j++);
int sum=0;
int len=j-i;
i=j;
for(int k=0;k<len;k++)
{
sum+=(v[j-1]-'0')*pow(10,k);
j--;
}
num.push_back(sum);
}//if
}//for
cout<<"该串共含有"<<num.size()<<"个整数 ";
for(int e=0;e<num.size();e++)
cout<<num[e]<<' ';
cout<<endl;
}本回答被提问者采纳
第3个回答 2010-12-04
#include<iostream>
using namespace std;
int main()
{
char str[100],*pstr;
int a[10],num,flag,flagpast,i,n;
num = flag = flagpast = i = n = 0;
pstr = str;
cout<<"please input a string:";
cin>>str;
while(*pstr)
{
if(flag = (*pstr >= '0' && *pstr <= '9')?1:0)
{
flagpast = flag;
num = num*10 + (*pstr - 48);
}
if((flag == 0) && (flagpast == 1))
{
a[i++] = num;
num = flag = flagpast = 0;
continue;
}
pstr++;
}
n = i;
for(i = 0; i <n ; i++)
{
cout<<a[i];
}
return 0;
}