解方程：x-2分之x+x-7分之x-9=x-1分之x+1+x-6分之x-8

解方程:x-2分之x+x-7分之x-9=x-1分之x+1+x-6分之x-8
x=4 结果正在上传 ……

数学解方程(x\/x-2)+(x-9\/x-7)=(x+1\/x-1)+(x-8\/x-6)
1.x\/(x-2)=1+2\/(x-2) x-9\/(x-7)= 1-2\/(x-7) x+1\/(x-1)=1+2\/(x-1) x-8\/(x-6)=1-2\/(x-6) 代入得1\/(x-2)-1\/(x-7)=1\/(x-1)-1\/(x-6) 移项得1\/(x-2)+1\/(x-6)=1\/(x-1)+1\/(x-7) 然后通分就好算了，注意x不等于1,2,6,7(分母不...

解方程:x\/(x-2)+(x-9)\/(x-7)=(x+1)\/(x-1)+(x-8)\/(x-6)
解：x\/(x-2)+(x-9)\/(x-7)=(x+1)\/(x-1)+(x-8)\/(x-6)因为x\/x-2=(x-2+2)\/x-2=1+2\/x-2.其他类似。即 1+2\/(x-2)+1-2\/(x-7)=1+2\/(x-1)+1-2\/(x-6)1\/(x-2)-1\/(x-7)=1\/(x-1)-1\/(x-6)可得－5\/(x-2)(x-7)＝-5\/(x-1)(x-6)(x-2)(...

分式方程。x\/(x-2)+(x-9)\/(x-7)=(x+1)\/(x-1)+(x-8)\/(x-6)
(x-9)\/(x-7)-(x+1)\/(x-1)=(x-8)\/(x-6)-x\/(x-2)[(x-9)(x-1)-(x+1)(x-7)]\/[(x-7)(x-1)]=[(x-8)(x-2)-x(x-6)]\/[(x-6)(x-2)][x^2-10x+9-x^2+6x+7]\/(x^2-8x+7]=(x^2-10x+16-x^2+6x]\/[x^2-8x+12](-4x+16)\/(x^2-8x+7)=(-...

解分式方程:x-10\/x-8+x-6\/x-4=x-7\/x-5+x-9\/x-7
化简一下变成1-2\/(x-8) +1-2\/(x-4)=1-2\/(x-5) +1-2\/(x-7)由此可以看出1\/(x-8)+1\/(x-4)=1\/(x-5)+1\/(x-7)左右整合可以得到分子都为2x-12 所以分母相同x^2+32-12x=x^2+35-12x 很明显不对 所以分子为0 x=6 ...

解分式方程x-7\/x-9+x-3\/x-5=x-4\/x-6+x-6\/x-8
将x-7\/x-9分解成1+2\/(x-9)其他分式同理 则原方程等价于 1\/x-9+1\/x-5=1\/x-6+1\/x-8 1\/x-6-1\/x-5=1\/x-9-1\/x-8 1\/(x-5)(x-6)=1\/(x-8)(x-9)(x-5)(x-6)=(x-8)(x-9)x=7

解分式方程:x-10\/x-8+x-6\/x-4=x-7\/x-5+x-9\/x-7
化简一下变成1-2\/(x-8)+1-2\/(x-4)=1-2\/(x-5)+1-2\/(x-7)由此可以看出1\/(x-8)+1\/(x-4)=1\/(x-5)+1\/(x-7)左右整合可以得到分子都为2x-12 所以分母相同x^2+32-12x=x^2+35-12x 很明显不对 所以分子为0 x=6 ...

解方程:x-19分之5x-96+x-9分之x-8=x-6分之4x-19+x-8分之2x-21
x=123\/14

分式方程 x-9分之x-7加上x-5分之x-3=x-6分之x-4加上x-8分之x-6
通分 (2x-14)\/(x-5)(x-9)=(2x-14)\/(x-8)(x-6)(2x-14)[1\/(x�0�5-14x+45)-1\/(x�0�5-14x+84)]=0 1\/(x�0�5-14x+45)≠1\/(x�0�5-14x+84)所以2x-14=0 x=7 分式方程要检验 经检验，x...

解方程,x-4\/x-5+x-8\/x-9=x-7\/x-8+x-5\/x-6.
其他的一样：x-8\/x-9=1+1\/(x-9)x-7\/x-8=1+1\/(x-8)x-5\/x-6=1+1\/(x-6)x-4\/x-5+x-8\/x-9=x-7\/x-8+x-5\/x-6 即1+1\/(x-5)+1+1\/(x-9)=1+1\/(x-8)+1+1\/(x-6)1\/(x-5)+1\/(x-9)=1\/(x-8)+1\/(x-6) ，上部两边同时减去2变形得 两边通分(2x-...