thinkphp5跳转带的参数为什么收不到呢
input('get.')和input('post.')都试了不行,只能用input('param.')可以要接收传递过去的id,然后进行编辑
第1个回答 2017-12-13
include <QtCore/QCoreApplication>
#include <QAxObject>
#include <Windows.h>
int main(int argc, char *argv[])
{
//OleInitialize(0);
//CoInitialize(0);
QCoreApplication a(argc, argv);
QAxObject *asdfg = new QAxObject("Excel.Application");
return a.exec();
}本回答被网友采纳
#include <QAxObject>
#include <Windows.h>
int main(int argc, char *argv[])
{
//OleInitialize(0);
//CoInitialize(0);
QCoreApplication a(argc, argv);
QAxObject *asdfg = new QAxObject("Excel.Application");
return a.exec();
}本回答被网友采纳
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