第1个回答 2019-09-21
你好 很高兴为你解答
2x²=3x-1
2x²-3x+1=0
x²-3/2x+1/2=0
（x-3/4）²+1/2-9/16=0
（x-3/4）²=1/16
x-3/4=±1/4
所以 x₁=1 x₂=1/2
2x²=3x-1
2x²-3x+1=0
x²-3/2x+1/2=0
（x-3/4）²+1/2-9/16=0
（x-3/4）²=1/16
x-3/4=±1/4
所以 x₁=1 x₂=1/2
第2个回答 2019-09-21
2x²＝3x－1
x² - 3x/2 + 1/2 = 0
x² - 3x/2 + 9/16 = 1/16
(x - 3/4)² = 1/16
x - 3/4 = ± 1/4
x = 3/4 ± 1/4
x1 = 1
x2 = 1/2追答
x² - 3x/2 + 1/2 = 0
x² - 3x/2 + 9/16 = 1/16
(x - 3/4)² = 1/16
x - 3/4 = ± 1/4
x = 3/4 ± 1/4
x1 = 1
x2 = 1/2追答
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本回答被网友采纳第3个回答 2019-09-21
解2x^2=3x一1
2x^2-3x+1=0
2(x^2-3/2x+1/2)=0
2((x^2-2*3/4+9/16)一9/16+8/16)
=2((x一3/4)^2-1/16)
2((x一3/4)+1/4)(x一3/4一1/4)
2(x一1/2)(x一1)
(2x一1)(x一1)追答
2x^2-3x+1=0
2(x^2-3/2x+1/2)=0
2((x^2-2*3/4+9/16)一9/16+8/16)
=2((x一3/4)^2-1/16)
2((x一3/4)+1/4)(x一3/4一1/4)
2(x一1/2)(x一1)
(2x一1)(x一1)追答
即x1=1/2，x2=1
第4个回答 2019-09-21
2x²=3x-1
2x²-3x+1=0
x²-3x/2+1/2=0
（x-3/4）²=-1/2+9/16
x-3/4=±√1/16
x1=3/4+1/4=1
x2=3/4-1/4=1/2
2x²-3x+1=0
x²-3x/2+1/2=0
（x-3/4）²=-1/2+9/16
x-3/4=±√1/16
x1=3/4+1/4=1
x2=3/4-1/4=1/2
第5个回答 2019-09-21
2x^2＝3x－1
2[x^2 - (3/2)x ] = -1
2[x^2 - (3/2)x +9/16] = -1 +9/8
2(x -3/4)^2 = 1/8
(x -3/4)^2 = 1/16
x-3/4 = 1/4 or -1/4
x= 1 or 1/2
2[x^2 - (3/2)x ] = -1
2[x^2 - (3/2)x +9/16] = -1 +9/8
2(x -3/4)^2 = 1/8
(x -3/4)^2 = 1/16
x-3/4 = 1/4 or -1/4
x= 1 or 1/2
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