求不定积分∫2xarctanxdx

如题所述

第1个回答  2019-07-06
∫2xarctanxdx
=∫arctanxdx^2
=x^2.arctanx -∫x^2/(1+x^2) dx
=x^2.arctanx -∫[1 - 1/(1+x^2)] dx
=x^2.arctanx -x +arctanx + C

求不定积分∫2xarctanxdx
=∫arctanxdx^2 =x^2.arctanx -∫x^2\/(1+x^2) dx =x^2.arctanx -∫[1 - 1\/(1+x^2)] dx =x^2.arctanx -x +arctanx + C

求不定积分∫2arctanxdx
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