1又二分之一+1\/6+2又1\/12+6又1\/20+4又1\/30+3又1\/42=
1又6分之1+2又12分之一+3又20分之一+4又30分之1+5又42分之一+6又56分之1+7又72分之一 =1+2+3+4+5+6+7+1\/6+...+1\/72 这里应该是1\/6=1\/2-1\/3 ...1\/72=1\/8-1\/9 =1+2+3+4+5+6+7+1\/6+...+1\/72袱叮递顾郛该店双锭晶 =28+1\/2-1\/3+1\/3-1\/4+......
1又2分之1+2又6分之1+3又12分之1+4又20分之1+5又30分之1+6又42分之1...
原题=1+1\/2+2+1\/6……7+1\/56 =1+2+3+4+5+6+7+1\/2+1\/2-1\/3+1\/3-1\/4+1\/4-1\/5……+1\/7-1\/8 =28+1\/2+1\/2-1\/8 =28又7\/8
1+2又6分之1+3又12分之1+4又20分子1+5又30分之1+6又42分之1+7又56分...
答案见图片
1又1\/6+2又1\/12+3又1\/20+4又1\/30+5又1\/42=?
=15又5\/14 因为1\/6=1\/2-1\/3, 1\/12=1\/3-1\/4... ...由此简算。第二题应该是打错了,应该是1+1\/3 因此原题可写成:1+1\/3-1\/3-1\/4+1\/4+1\/5... ...+1\/8+1\/9 =1+1\/9 =1又1\/9 第三题同理:3\/2写成1+1\/2,-5\/6写成-1\/2-1\/3 因此原题写成:1+1\/2-1\/...
1+2又6分之1+3又12分之1+4又20分之1+5又30分之1+6又42分之1+7又56分...
原式=(1+2+3+...+9)+(1\/6 +1\/12+1\/20+...+1\/90)=45+[1\/(2×3)+1\/(3×4)+1\/(4×5)+...+1\/(9×10)]=45+1\/2 -1\/3 +1\/3 -1\/4+ 1\/4 -1\/5+...+1\/9 -1\/10 =45+ 1\/2 -1\/10 =45又5分之2 ...
1+2又6分之1+3又12分之1+4又20分之1+5又30分之1+6又42分之1+7又56分...
=1+2+1\/2-1\/3+3+1\/3-1\/4+4+1\/4-1\/5+5+1\/5-1\/6+6+1\/6-1\/7+7+1\/7-1\/8+8+1\/8-1\/9+9+1\/9-1\/10 =45+2\/5
1+2又6分之1+3又12分之1+4又20分之1+5又30分之1+6又42分之1+7又56分...
=1+2+3+4+5+6+7+8+1\/6+1\/12+1\/20+1\/30+1\/42+1\/56+1\/72 =36+1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7+1\/7-1\/8+1\/8-1\/9 =36+1\/2-1\/9 =36又7\/18
1+2又6分之1+3又12分之1+4又20分之1+5又30分之1+6又42分之1
解:原式=1+2+3+4+5+6+1\/6+1\/12+1\/20+1\/30+1\/42 =21+1\/3+1\/42 =21+5\/14 如果你觉得我的回答比较满意,希望你给予采纳,因为解答被采纳是我们孜孜不倦为之付出的动力!
1+2又6分之1+3又12分之1+4又20分之1+5又30分之1+6又42分之1+7又56分...
=1+2+3+4+5+6+7+8+9+ 1\/6+1\/12+1\/20+1\/30+1\/42+1\/56+1\/72+1\/90 =45+1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7+1\/7-1\/8+1\/8-1\/9+1\/9-1\/10 =45+1\/2-1\/10 =45又2\/5 有问题,可追问,如满意,请采纳,谢谢!
1+2又6\/1+3又12\/1+4又20\/1+5又30\/1+6又42\/1+7又56\/1 +8又72\/1+9又90...
1+2+3+...+9=45 1\/6+1\/12+...+1\/90 =1\/2-1\/3+1\/3-1\/4+...+1\/9-1\/10 =1\/2-1\/10 =2\/5 1+2又6\/1+3又12\/1+4又20\/1+5又30\/1+6又42\/1+7又56\/1+8又72\/1+9又90\/1=45又5\/2