$('table').attr('id','id_name');
追问class:'tableStyle',
$('table').attr("id","mytable"),
这样写也是那里报错
追答在定义table的后面:
table.attr('id','mytable');
追问求这两句完整代码
追答var table = $('<table id="mytable" class="tableStyle"></table>');
var table = $('<table></table>').addClass('tableStyle').attr('id','myTable');本回答被提问者采纳