第1个回答 2013-12-23
答：设t=√x，x=t^2
∫[1/(√x+x)]dx
=∫[1/(t+t^2)] d(t^2)
=∫[1/(t+t^2)] 2tdt
=2∫[1/(1+t)] d(t+1)
=2ln(t+1)+C
=2ln(√x+1)+C本回答被提问者采纳
∫[1/(√x+x)]dx
=∫[1/(t+t^2)] d(t^2)
=∫[1/(t+t^2)] 2tdt
=2∫[1/(1+t)] d(t+1)
=2ln(t+1)+C
=2ln(√x+1)+C本回答被提问者采纳
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