解下列分式方程:(1)X/(X-2)+(X-9)/(X-7)=(X+1)/(X-1)+(X-8)/(X-6)

还有几道 (2)(X+2)/(X+1)-(X+4)/(X+3)=(X+6)/(X+5)-(X+8)/(X+7) 解关于X的方程(2a)/(x-1)=2-a

第1个回答  2019-07-13
(1)通分得
x^2-7x+x^2-11x+18=x^2-5x-6+x^2-9x+8
解得
x=4;
(2)左右分别通分得2/[(x+1)(x+3)]=2/[(x+5)(x+7)],
则分母相等且不为零,解得
x=-4;
(3)x=(2+a)/(2-a),a不等于2。

解下列分式方程:(1)X\/(X-2)+(X-9)\/(X-7)=(X+1)\/(X-1)+(X-8)\/(X-6...
1.x\/(x-2)=1+2\/(x-2)x-9\/(x-7)= 1-2\/(x-7)x+1\/(x-1)=1+2\/(x-1)x-8\/(x-6)=1-2\/(x-6)代入得1\/(x-2)-1\/(x-7)=1\/(x-1)-1\/(x-6)移项得1\/(x-2)+1\/(x-6)=1\/(x-1)+1\/(x-7)然后通分就好算了,注意x不等于1,2,6,7(分母不为0),最后要作为...

分式方程。x\/(x-2)+(x-9)\/(x-7)=(x+1)\/(x-1)+(x-8)\/(x-6)
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解下列分式方程:(1)1\/x-2 + 1\/x-6=1\/x-7 + 1\/x-1(要有过程,谢谢!)
等号左边分子分母同乘以(x-1)(x-2),等号右边分子分母同乘以(x-6)(x-7)得1\/(x^2-3x+2)=1\/(x^2-13x+42)也就是x^2-3x+2=x^2-13x+42 易得出x=4

解分式方程 (x-4)\/(x-5)+(x-8)\/(x-9)=(x-7)\/(x-8)+(x-5)\/(x-6) (3...
1+1\/(x-5)+1+1\/(x-9)=1+1\/(x-8)+1+1\/(x-6)就是 1\/(x-5)-1\/(x-6)=1\/(x-8)-1\/(x-9)就是 1\/(x-5)(x-6)=1\/(x-8)(x-9)就是 (x-5)(x-6)=(x-8)(x-9)就是 x^2-11x+30=x^2-17x+72 6x=42 x=7 (3*x-1)\/(3*x+2)-(x+9)\/(x+3)=0...

分式方程(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+
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解分式方程:x-10\/x-8+x-6\/x-4=x-7\/x-5+x-9\/x-7
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解分式方程:x-10\/x-8+x-6\/x-4=x-7\/x-5+x-9\/x-7
化简一下变成1-2\/(x-8)+1-2\/(x-4)=1-2\/(x-5)+1-2\/(x-7)由此可以看出1\/(x-8)+1\/(x-4)=1\/(x-5)+1\/(x-7)左右整合可以得到分子都为2x-12 所以分母相同x^2+32-12x=x^2+35-12x 很明显不对 所以分子为0 x=6 ...

解分式方程:(x+1)\/(x+2)+(x+6)\/(x+7)=(x+2)\/(x+3)+(x+5)\/(x+6)
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(x+1)\/(x+2)+(x+6)\/(x+7)=
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