(1\/9+5\/6-7\/12)除以1\/36用简便法计算怎么算
=(1\/9+5\/6-7\/12)*36 =1\/9*36+5\/6*36-7\/12 *36 =4+30-21 =34-21 =13
(1\/2-5\/9+5\/6-7\/12)*(-36)=?及计算过程
=7\/36*(-36)= -7
(1\/2 - 5\/9 + 5\/6 - 7\/12)÷(-1\/36)
(1\/2 - 5\/9 + 5\/6 - 7\/12)÷(-1\/36)=(18\/36-20\/36+30\/36-21\/36)×(-36)=-18+20-30+21 =-7;您好,很高兴为您解答,skyhunter002为您答疑解惑 如果本题有什么不明白可以追问,如果满意记得采纳 如果有其他问题请采纳本题后另发点击向我求助,答题不易,请谅解,谢谢。祝学...
(1\/9+5\/6-7\/12)除以1\/36?
(1\/9+5\/6-7\/12)÷1\/36 =(1\/9+5\/6-7\/12)×36 =1\/9×36+5\/6×36-7\/12×36 =4+30-21 =4+9 =13
括号4\/9加5\/6减7\/18括号除以1\/36怎么简便计算?
括号4\/9加5\/6减7\/18括号除以1\/36怎么简便计算?括号4\/9加5\/6减7\/18括号除以1\/36 =36*4\/9+36*5\/6-36*7\/18 =16+30-14 =32
括号1\/9+5\/6-7\/18括号乘三十六怎样简便怎样算
(1\/9+5\/6-7\/18)×36 =1\/9×36+5\/6×36-7\/18×36 =4+30-14 =20
(1\/2-5\/9+5\/6-7\/12)x(-36)
望采纳谢谢
(7\/12-5\/36)÷1\/6怎么简便
简算过程如下:(7\/12-5\/36)÷1\/6 =(7\/12-5\/36)×6 =7\/12×6-5\/36×6 =7\/2-5\/6 =8\/3=2又2\/3 (除以一个分数等于乘以这个分数的倒数,1\/6的倒数就是6。其实就是乘法结合律,再利用约分简便计算)
括号1\/2-3+5\/6-7\/12括号除减36分之1
(1\/2-3+5\/6-7\/12)÷(-1\/36)=(1\/2-3+5\/6-7\/12)×(-36)=1\/2×(-36)-3×(-36)+5\/6×(-36)-7\/12×(-36)=-18+108-30+21 =81