=[（a-1)(a^2-1)+2a(a+1)]/(a+1)(a-1)
=[(a-1)(a-1)(a+1)+2a(a+1)]/(a+1)(a-1)
=[(a-1)^2+2a}/a-1
把a=2带入得（2-1)^2+4=5
(a^2-2a+1)\/a-1+(a^2+1)\/a+1
=(a^2-1+a^2+1)\/(a+1)=2a^2\/(a+1)
当a=2\/(1-√3)时,求a^2\/(a-1)-(a^2+a)\/√(a^+2a+1)-a\/1的值
a=2\/(1-√3)=-1-√3 所以a+1=-√3<0 |a+1|=-a-1 原式=a²\/(a-1)-a(a+1)\/√(a+1)²-a =a²\/(a-1)-a(a+1)\/|a+1|-a =a²\/(a-1)+a(a+1)\/(a+1)-a =a²\/(a-1)+a-a =a²\/(a-1)=(4+2√3)\/(-2-√3)=-2 ...
计算:a^2-1\/a^2+2a+1除a^2-a\/a+1
解：原式=[(a²-1)\/(a²+2a+1)]÷[(a²-a)\/(a+1)]=[(a+1)(a-1)\/(a+1)²]÷[a(a-1)\/(a+1)]=[(a-1)\/(a+1)]×{ (a+1)\/[a(a-1)] } =1\/a
当a=2\/(1-√3)时,求(a∧2-1)\/(a-1)-√(a∧2+2a+1)\/(a∧2+a-1\/a)的值
=2(1+√3)\/(1-3)=-(1++√3)=-1-√3 则a+1=-√3<0 |a+1|=-(a+1)原式=(a+1)(a-1)\/(a-1)-√(a+1)²\/[a(a+1)]-1\/a =(a+1)-|a+1|\/[a(a+1)]-1\/a =(a+1)-[-(a+1)]\/[a(a+1)]-1\/a =(a+1)+(a+1)\/[a(a+1)]-1\/a =(a+1)+1...
请你先将分式:a^2一2a十1\/a一1十a^2十a\/a十1化简,再选取一个你喜欢且...
（a^2-2a+1）\/（a-1）+（a^2+a）\/（a+1）=（a-1）+a=2a-1
(2a+2)\/(a-1)\/(a+1)-(a^2-1)\/(a^2-2a+1)
(2a+2)\/(a-1)\/(a+1)-(a^2-1)\/(a^2-2a+1)=2(a+1)\/[(a-1)(a+1)]-(a-1)(a+1)\/(a-1)^2 =2\/(a-1)-(a+1)\/(a-1)=[2-(a+1)]\/(a-1)=[2-a-1]\/(a-1)=(1-a)\/(a-1)=-(a-1)\/(a-1)=-1 ...
求值化简:a-1分之2a+2÷(a+1)+a²-2a+1分之a²-1
求值化简:a-1分之2a+2÷(a+1)+a²-2a+1分之a²-1 然后a在-112三个数中任选一个合适的数代入求值... 然后a在 -1 1 2 三个数中任选一个合适的数代入求值 展开 我来答 1个回答 #热议# 网文质量是不是下降了?wangcai3882 2014-02-15 · 知道合伙人教育行家 ...
1\/(a^2-2a+1),1\/(a^2-1),1\/(a^2+2a+1)的最简公分母是
分别化简成：1\/(a-1)²，1\/(a+1)(a-1)，1\/(a+1)²，最简公分母为（a-1)²(a+1)²
当a=2\/(1-√3)时,求(a^2-1)\/(a-1)-√(a^+2a+1)\/(a^2+a)-1\/a的值 求...
（a^2-1）\/(a-1)-√(a^+2a+1)\/(a^2+a)-1\/a =（a+1）(a-1）\/(a-1)-√(a+1)^\/(a^2+a)-1\/a =（a+1)-(-(a+1))\/[a(a+1)]-1\/a =a+1+1\/a-1\/a =a+1 =2(1+√3)\/[1+√3)(1-√3)]+1=-1-√3+1=-√3 ...
已知a^2+2a-1=0,求分式[(a-2)\/(a^2+2a)-(a-1)\/(a^2+4a+4)]\/(a-4...
已知a^2+2a-1=0,求分式[（a-2）\/(a^2+2a)-(a-1)\/(a^2+4a+4)]\/(a-4)\/(a+2）的值。 解： 因为a^2+2a-1=0, 所以a^2+2a=1 所以[(a-2)\/(a^2+2a)-(a-1)\/(a^2+4a+4)]\/[(a-4)\/(a+2) =[(a-2)\/a(a+2)-(a-1)\/(a+2)^2]*[(a+2)\/(a-...
