因式分解x^2-6x(y-z)+9(y-z)^2

原式=(x-3x(y-z)+3(y-z))^2

x^2-6x(y-z)+9(y-z)^2
=x^2-6x(y-z)+[3(y-z)]^2
=(x-3y+3z)^2

(a+b)^2-4(a+b)c+4c^2
=(a+b)^2-4(a+b)c+(2c)^2
=(a+b-2c)^2本回答被提问者采纳

x^2-6x(y-z)+9(y-z)^2
=[x-3(y-z)]^2
=(x-3y+3z)^2