1÷(1-1/2)÷(1-1/3)÷(1-1/5)······(1-1/2006),这道题该怎么做?中间的省略号应该

如题所述

第1个回答  2011-10-03
不就是1*(2)*(3/2)*(4/3)*(5/4)..........*(2006/2005)=2006
第2个回答  2011-10-02
1÷(1-1/2)÷(1-1/3)÷(1-1/4)÷(1-1/5)······÷(1-1/2006),
=1÷(1/2)÷(2/3)÷(3/4)÷(4/5)······÷(2005/2006)
=1x2x(3/2)x(4/3)x(5/4)x.........x(2006/2005)
=2006追问

拜托,中间没有÷(1-1/4)

追答

应该是题目漏印了!
如果没有÷(1-1/4)

1÷(1-1/2)÷(1-1/4)÷(1-1/5)······÷(1-1/2006),
=[1÷(1/2)÷(2/3)÷(3/4)÷(4/5)······÷(2005/2006)] x(3/4)
=[1x2x(3/2)x(4/3)x(5/4)x.........x(2006/2005)] x(3/4)
=2006 x(3/4)
=1504.5

追问

是没有÷(1-1/4),不是没有÷(1-1/3)

追答

对不起,打错了,不影响得数!
1÷(1-1/2)÷(1-1/3)÷(1-1/5)······÷(1-1/2006),
=[1÷(1/2)÷(2/3)÷(3/4)÷(4/5)······÷(2005/2006)] x(3/4)
=[1x2x(3/2)x(4/3)x(5/4)x.........x(2006/2005)] x(3/4)
=2006 x(3/4)
=1504.5

追问

假如不是印漏的问题呢

追答

这里就是按照不是印漏的情况来解题的啊!

本回答被网友采纳
第3个回答  2011-10-04
1x2x(3/2)x(4/3)x(5/4)......x(2006/2005)
=1x2006
=2006
第4个回答  2012-04-07
1÷(1-1/2)÷(1-1/3)÷(1-1/5)······÷(1-1/2006),
=[1÷(1/2)÷(2/3)÷(3/4)÷(4/5)······÷(2005/2006)] x(3/4)
=[1x2x(3/2)x(4/3)x(5/4)x.........x(2006/2005)] x(3/4)
=2006 x(3/4)
=1504.5

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