先化简,再求值:y(x-y)-x(x+y)/x平方-y平方除以x平方+y平方/x+y,其中x=2,y=1

如题所述

第1个回答  2012-03-14
[y(x-y)-x(x+y)]/(x^2-y^2)÷(x^2+y^2)/x+y
=(yx-y^2-x^2-xy)/(x+y)(x-y)*(x+y)/(x^2+y^2)
=-(x^2+y^2)/(x+y)(x-y)*[(x+y)/(x^2+y^2)]
=-1/(x-y)
=-1

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