计算：⑴cos^2 30°+sin^2 30°-tan45° ⑵cos30°-sin°45/sin°60-Cos°45。务必要有计算过程！谢谢！

cos^2 30°+sin^2 30°-tan45°=1-1=0
（cos30°-sin°45）/（sin°60-Cos°45）是这样的么？=(√3/2-√2/2)/(√3/2-√2/2)=1
因为cos^2 x+sin^2 x=1

1）
cos30=√3/2 sin30=1/2 tan45=1
(3/4)+1/4-1=0

2)sin45=cos45=√2/2 sin60=√3/2
(√3/2-√2/2)/(√3/2-√2/2)=1本回答被提问者采纳

⑴cos^2 30°+sin^2 30°-tan45°
=1-1
=0
⑵(cos30°-sin45°)/(sin60°-Cos45°)
=[sin(90°-30°)-sin45°]/[(sin60°-sin(90°-45°)]
=(sin60°-sin45°)/(sin60°-sin45°)
=1