31又1/2÷3/2+41又1/3÷4/3+51又1/4÷5/4

31又1\/2÷3\/2+41又1\/3÷4\/3+51又1\/4÷5\/4
31又1\/2÷3\/2+41又1\/3÷4\/3+51又1\/4÷5\/4 =(30+1又1\/2)×2\/3+(40+1又1\/3)×3\/4+(50+1又1\/4)×4\/5 =20+3\/2×2\/3+30+4\/3×3\/4+40+5\/4×4\/5 =20+1+30+1+40+1=93 祝你好运，学习进步

31又1\/2÷3\/2+41又1\/3÷4\/3+51又1\/4÷5\/4
31又1\/2÷3\/2+41又1\/3÷4\/3+51又1\/4÷5\/4 =63\/2 X 2\/3+124\/3 X 3\/4+205\/4 X 4\/5 =63\/3+124\/4+205\/5 =21+31+41 =93

31又1\/2÷3\/2+41又1\/3÷4\/3+51又1\/4÷5\/4
EXCEL中输入=31.5\/1.5+(41+1\/3)\/(4\/3)+51.25*4\/5 结果：93 题目身并不难，你得把几又几分之几转化成一个数字比较容易 1又二分之一，就是1+1\/2=1.5 X又Y（Y小于1），就是X+Y（小于X+1）另外X÷3\/4 就等于X*4\/3 ...

...又二分之一÷2分之3+41又三分之一÷3分之4+51又四分之一?
31又1\/2÷3\/2+41又1\/3÷4\/3+51又1\/4 =63\/2÷3\/2+124\/3÷4\/3+51又1\/4除以一个数等于除以它的倒数 =63\/2*2\/3+124\/3*3\/4+51又1\/4 =21+31+51又1\/4带分数的整数部分可以直接与整数加减运算。=103又1\/4

六年级上寒假作业,15分
=11\/21+1\/6 =22\/42+7\/42 29\/42 第二题：31又1\/2除3\/2+41又1\/3除4\/3+51又1\/4除5\/4 =63\/2*2\/3+124\/3*3\/4+205\/4*4\/5 =21+31+41 =93 对不起，这道题得数不是分数，不能满足您提出的要求，望您能谅解。

31又1\/2x2\/3+41又1\/3x3\/4+51又1\/4×4\/5+61又1\/5x5\/6+71又1\/
1 2011-06-28 简便运算:31又1\/2*+41又1\/3*3\/4+51又1\/4... 3 2020-01-19 41又1\/3x3\/4+51又1\/4x4\/5+61又1\/5X5... 6 2016-11-21 用简便方法计算.41又1\/3x3\/4+51又1\/4x4\/5+... 14 2015-05-29 "1\/4x4又1\/3+1\/5x5又1\/4+1\/6x6又1\/5... 2 2012-11-04 41...

...对不起啊亲 是 31又1\/2*2\/3+51又2\/3+71又3\/4*4\/7
31又1\/2*2\/3+51又2\/3+71又3\/4*4\/7 =63\/2*2\/3+51又2\/3+287\/4*4\/7 =63\/3+155\/3+41 =（63+155）\/3+41 =218\/3+41 =72又2\/3+41 =113又2\/3

巧算31X1\/2X1\/3+41X1\/3X1\/4+51X1\/4X1\/5=?
31*1\/2*1\/3 + 41*1\/3*1\/4 + 51*1\/4*1\/5=(30+1)*1\/2*1\/3 + (40+1)*1\/3*1\/4 + (50+1)*1\/4*1\/5=5+1\/6 + 10\/3+1\/12 + 5\/2+1\/20=300\/60 + 10\/60 + 200\/60 + 5\/60 + 150\/60 + 3\/60=668\/60=167\/15 ...

51又2\/3*3\/5+41又1\/3*3\/4+31又1\/2*2\/3=?
31+31+21=83

51又1\/4*4\/5+41又1\/3*3\/4+31又1\/2*2\/3 2013*2011\/2012+1\/2012简算
51又1\/4*4\/5+41又1\/3*3\/4+31又1\/2*2\/3 =(50+5\/4)*4\/5+(40+ 4\/3)*3\/4 +(30+ 3\/2)*2\/3 =40 + 1 + 30 +1 + 20 +1=93.2013*2011\/2012+1\/2012=(2012+ 1)*2011\/2012+1\/2012=2011 + 2011\/2012+1\/2012=2011 +1=2012 ...