解下列方程x²-（√2 √3）x √6=0

(1)X^2-6X+4=0X²-6X+9-5=0(X-3)²=5X-3=±√5X1=3+√5X2=3-√5(2)X^2+5X-6=0 X²+5X=6 X²+5X+(5/2)²=6+25/4(X+5/2)²=49/4X+5/2=±7/2X1=-5/2+7/2=1X2=-5/2-7/2=-6(3)2t^2-7t-4=0t²-7t/2-2=0t²-7t/2+(7/4)²=2+49/16(t-7/4)²=81/16t-7/4=±9/4t1=7/4+9/4=4t2=7/4-9/4=-1/2(4)3X^2-1=6X X²-2X-1/3=0X²-2X+1=1/3+1(X-1)²=4/3X-1=±√(4/3)X1=1+2√3/3X2=1-2√3/3本回答被网友采纳