double sum = 0;//接收结果
for(int i = 1 ; i<=10 ; i++){
int n = i*2 + 1;//计算分母
sum += i/n;//把一项的结果加起来
}
System.out.print("结果是：" + sum);
public static void main(String[]args){
double a=0.0 ;
for(double i=1;i<=10;i++){
a=a+i/(2*i+1);
}
System.out.print("1/3+2/5+3/7+……+10/21=" + a);
}
}
计算1\/3+2\/5+3\/7+……+10\/21的matlab程序
用symsum（）——求和函数来求解。syms n symsum(n\/(2*n+1),1,20)
JAVA 求1\/2+2\/3+3\/5+5\/8+8\/13+13\/21 ... 前20项之和。
分析规律：分子为前两个分子之和，分母为前两个分母之和。public static void main(String[] args) { double sum = 0; int n = 1; int m = 1; int j; for(int i=1; i<=20; i++) { sum = sum + m\/(double)(m+n); j = m; m =...
1\/3+3\/4+2\/5+5\/7+9\/20+10\/21+11\/24+19\/35=? 求简便计算
=1\/3+1\/3+1\/3+3\/4+1\/4+2\/5+1\/5+5\/7+1\/7+1\/8+19\/35 =1+1+3\/5+6\/7+1\/8+19\/35 =2+21\/35+30\/35+19\/35+1\/8 =2+70\/35+1\/8 =4+1\/8 =33\/8
1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+12\/35=
解: 1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+12\/35 =1\/3+3\/4+2\/5+5\/7+7\/8+(1\/4+1\/5)+(1\/3+1\/7)+(1\/3+1\/8)+(1\/5+1\/7)=(1\/3+1\/3+1\/3)+(1\/4+3\/4)+(2\/5+1\/5+1\/5)+(5\/7+1\/7+1\/7)+(7\/8+1\/8)=4+4\/5 =4又4\/5 ...
1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+12\/35怎么简算
=1\/3+3\/4+2\/5+5\/7+7\/8+1\/4+1\/5+1\/3+1\/7+1\/3+1\/8+1\/5+1\/7 =4\/5 小学数学简便方法归纳 1、提取公因式：这个方法实际上是运用了乘法分配律，将相同因数提取出来，考试中往往剩下的项相加减，会出现一个整数。2、借来借去法：看到名字，就知道这个方法的含义。用此方法时，需要...
1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+19\/35等于多少?求过程。
1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+19\/35 =1\/3+3\/4+2\/5+5\/7+7\/8+(4\/20+5\/20)+(3\/21+7\/21)+ (3\/24+8\/24)+(5\/35+14\/35)=1\/3+3\/4+2\/5+5\/7+7\/8+1\/5+1\/4+1\/7+1\/3+1\/8+1\/3+2\/5+1\/7 =1\/3*3+(3\/4+1\/4)+(2\/5+1\/5+2\/5)+...
1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+19\/35
1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+19\/35 =1\/3+3\/4+2\/5+5\/7+7\/8+(1\/4+1\/5)+(1\/3+1\/7)+(1\/3+1\/8)+(2\/5+1\/7)=(1\/3+1\/3+1\/3)+(3\/4+1\/4)+(2\/5+1\/5+2\/5)+(5\/7+1\/7+1\/7)+(7\/8+1\/8)=1+1+1+1+1 =5 ...
1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+19\/35
1\/3+3\/4+2\/5+5\/7+7\/8+9\/20+10\/21+11\/24+19\/35 =(1\/3+3\/4+7\/8+11\/24)+(2\/5+9\/20)+(5\/7+10\/21+19\/35)=(8\/24+18\/24+21\/24+11\/24)+(8\/20+9\/20)+(75\/105+50\/105+57\/105)=29\/12+17\/20+26\/15 =145\/60+51\/60+104\/60 =300\/60 =5 ...
两道简单的数学题,答得好加分
=(32\/21+19\/35)+(32\/20+32\/24)=1\/7*(32\/3+19\/5)+8*(1\/5+1\/6)=1\/7*217\/15+44\/15 =31\/15+44\/15 =75\/5 =5 2.将底面直径为8，高为(18+22)=40的圆柱从中间切开全等的两部分 该几何体可以看成是这全等的两部分中的一个（若不明白再问，画图给你看）设该几何体体积为V...
