如题所述
代码如下
void main() {
int a, b, c,d=0;
for (a = 0; a <= 4; a++) {
for (b = 0; b <= 10; b++) {
for (c = 0; c <= 20; c++)
if (5 * a + 2 * b + c==20) {
printf("有%d个1元+%d个2元+%d个5元\n", c, b, a);
d++;
}
printf("共%d种方案", d);