(2又1/3-3又1/2+1又4/45)÷(-1又4/6)
=(2又1/3-3又1/2+1又4/45)×(-3/5)
=(7/3-7/2+49/45)×(-3/5)
=7/3×(-3/5)-7/2×(-3/5)+49/45×(-3/5)
=-7/5+21/10-49/75
=7/10-49/75
=105/150-98/150
=7/150
=(2又1/3-3又1/2+1又4/45)×(-3/5)
=(7/3-7/2+49/45)×(-3/5)
=7/3×(-3/5)-7/2×(-3/5)+49/45×(-3/5)
=-7/5+21/10-49/75
=7/10-49/75
=105/150-98/150
=7/150
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第1个回答 2020-04-30
我的不简单么?
（1）
（（2+1/3）-（3+1/2）+（1+4/45））/[-(1+1/6)]
=-(7/3-7/2+49/45)*(6/7)
｛化成假分数｝
=-(6/3-6/2+7*6/45)
｛乘法分配率｝
=-(2-3+14/15)=1/15
②[(2+1/27)-(7/9-11/12+1/6)*36]/5
｛化成假分数｝
=[55/27-(7*4-11*3+1*6)]/5
｛乘法分配率｝
=(55/27-1)/5
=(28/27)/5
=28/135
（1）
（（2+1/3）-（3+1/2）+（1+4/45））/[-(1+1/6)]
=-(7/3-7/2+49/45)*(6/7)
｛化成假分数｝
=-(6/3-6/2+7*6/45)
｛乘法分配率｝
=-(2-3+14/15)=1/15
②[(2+1/27)-(7/9-11/12+1/6)*36]/5
｛化成假分数｝
=[55/27-(7*4-11*3+1*6)]/5
｛乘法分配率｝
=(55/27-1)/5
=(28/27)/5
=28/135
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